Ask question

Ask question

All categories

2 years ago

9

collect some of chalk, limestone, marble, eggshells and seashells and mix them with a dilute acid. pass the gas produced into a

small amount of limewater to test for carbon dioxide. is carbon dioxide gas produced in each case.

1 answer:

Liula [17]2 years ago

4 0

Explanation:

Yes carbon dioxide found in each case

You might be interested in

Which compound is an Arrhenius base?(1) CH3OH (3) LiOH<br> (2) CO2 (4) NO2

nydimaria [60]

Lithium Hydroxide (LiOH) is an Arrhenius base

7 0

3 years ago

Read 2 more answers

Scientist use their knowledge of the half-life of carbon and uranium isotopes to measure the age of the rock or fossil .

marusya05 [52]

They can use them to find the age of fossils.

8 0

3 years ago

Is it true or false a population is all of the plants and animals that live within a ecosystem

Mars2501 [29]

The correct answer would have to be true

4 0

3 years ago

Read 2 more answers

The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles

sergejj [24]

<u>Answer:</u> The expression for equilibrium constant is $K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}$

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For the general chemical equation:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_c$ is given as:

$K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

For the given chemical reaction:

$2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)$

The expression for $K_{eq}$ is given as:

$K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}$

The concentration of solid is taken to be 0.

So, the expression for $K_{eq}$ is given as:

$K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}$

3 0

3 years ago

Which of these is a bacteria?<br><br> E-coli<br> HIV<br> Yeast<br> Zika

ZanzabumX [31]

<h3>Answer:</h3><h3></h3><h2>E. Coli </h2>

<h2>its a easy and faster answer to look at (;</h2>

5 0

3 years ago

Read 2 more answers