Answer is: 4.45 grams of methane gas <span>need to be combusted</span>.
Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
Ideal gas law: p·V =
n·R·T.<span>
p = 1.1 atm.
T = 301 K.
V(H</span>₂O) <span>= 12.5 L.
R = 0,08206 L·atm/mol·K.
</span>n(H₂O) = <span>1.1 atm ·
12.5 L ÷ 0,08206 L·atm/mol·K · 301 K.
</span>n(H₂O) = 0.556 mol.
From chemical reaction: n(H₂O) : n(CH₄) = 2 : 1.
n(CH₄) = 0.556 mol ÷ 2 = 0.278 mol.
m(CH₄) = 0.278 mol · 16 g/mol.
m(CH₄) = 4.448 g.
Well people say the world's going to end soon so people need to find another planet to live on they're thinking about Mars at the moment
Use PV = nRT
(2 atm)(.3 liters) = n(8.314 mol*K)(303°K)
.6 = n(2519.142)
Divide by 2519.142
n = .00023818 mols of HCl * 36.46g of HCl/ 1 mol of HCl
Grams of HCl = 0.00868
Describe how the catalyst, zymase speeds up the
reaction shown
The catalyst zymase speeds up the
reaction by catalyzing the fermentation of sugar into ethanol and carbon
dioxide. It is mostly present in yeasts.
<span>A reducing agent loses electrons, so on the left side of the equation N in HNO2 has an oxidation number of +3 and on the right side in NO3^- it has an oxidation number of +5, so it has lost electrons. Thus, the reducing agent would be HNO2.</span>
