A) Find an equation for the speed of the liquid as a function of the distance y it has fallen
Initial velocity of object vi=10.0 cm/s
initial position fo vector of the object is xi=3.09 cm
Final position of vector xf=-5.00cm
then displacement of object s = xf-xi=-5.00-3.09=-8.09cm
time t=2.55 s
s=vit+1/2at2
-5.00 = 11*2.55+1/2*a2.552
a = (-5.00 - 10*2.55*2)/2.552 = 2.94 cm
Acceleration is 2.94 cm.
<h3>What is a
cceleration?</h3>
Speed increase is the name we provide for any cycle where the speed changes. Since speed is a speed and a bearing, there are simply two different ways for you to speed up: change your speed or shift your course or change both. In mechanics, speed increase is the pace of progress of the speed of an item concerning time. Speed increases are vector amounts. The direction of an item's speed increase is given by the direction of the net power following up on that article. An item's typical speed increase throughout some stretch of time is its adjustment of speed separated by the term of the period. Numerically, quick speed increase, in the meantime, is the constraint of the typical speed increase over a little time period. In the terms of analytics, immediate speed increase is the subordinate of the speed vector concerning time.
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The velocity curve is such in which the x-axis is the velocity and the y is the time. The distance traveled by the object is calculated by multiplying velocity and time. Thus, in the velocity curve, the distance can be easily calculated if we know where to look.
The answer is A. Newton's third law of motion states that for every action, there is an equal and opposite reaction. A rocket exerts a large force on the gas that is in the rocket chamber (action). The gas thus exerts a large reaction force forward on the rocket (reaction). The large reaction force is called thrust.