(a) Rate as measured by an observer in the same ship will be same because as an observer in ship will not be moving relative to the astronaut, therefore their relative speed is zero and hence rate must be same.
(b) To calculate the rate measured by an observer at rest on the Earth we use the formula time dilation in relativity
Here, v is the speed of astronaut and c is the speed of light.
Substituting the given values in above formula we get
As one heartbeat takes (1/70)min = (6/7)s = 0.857 s in appropriate time, at that point to the observer on Earth it takes (2.29)(0.857 s) = 1.96 sec, and in this way her heartbeat is 30 beats/min.
Answer: the answer is A, C, E
Explanation:
Time management is apart of your study schedule so you will need to determine when to study, same goes with how to use ur study time, lastly it helps create ur study schedule to help find out what time you are free to study. :)
100W translates to 100 watts consumed in 1 hour. Assuming the printer consumes electrical energy at a steady rate, then: 100 ÷ 60 = 1.6667 watts per minute. 1.6667 ÷ 2 = 0.8333 watts consumed in 30 seconds.
Answer:
Explanation:
Your question is incomplete. I think you want to ask a following question.
Q. Which has greater kinetic energy, an object with a mass of 2.0 kg and a velocity of 1.0 m/s or an object with a mass of 0.1 kg and a velocity of 0.2 m/s.
Ans.
So the object having the greater velocity would have greater kinetic energy.
Let's prove it with the help of formula.
Fist case:
Second case: