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3 years ago

OT protons (d) (a) and (b)

Chemistry

2 answers:

insens350 [35]3 years ago

6 0

<h2>b is the correct answer</h2>

according In my course I studying it all

Dafna1 [17]3 years ago

3 0

Answer:

Explanation:

sana makatulong sayo

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3S8 + 8 OH- + 8 S3 + 4 HOOH

NemiM [27]

Answer:

Second order

Explanation:

We could obtain the order of reaction by looking at the table very closely.

Now notice that in experiment 1 and 2, the concentration of [OH^-] was held constant while the concentration of [S8] was varied. So we have;

a situation in which the rate of reaction was tripled;

0.3/0.1 = 2.10/0.699

3^1 = 3^1

Therefore the order of reaction with respect to [S8] is 1.

For [OH^-], we have to look at experiment 2 and 3 where the concentration of [S8] was held constant;

x/0.01 = 4.19/2.10

x/0.01 = 2

x = 2 * 0.01

x = 0.02

So we have;

0.02/0.01 = 2^1

2^1 = 2^1

The order of reaction with respect to [OH^-] = 1

So we have the overall rate law as;

Rate = k[S8]^1 [OH^-] ^1

Overall order of reaction = 1 + 1 = 2

Therefore the reaction is second order.

4 0

3 years ago

How come flowers usually contain more stamen the pistils

USPshnik [31]

<span>To make sure there are enough pollen to fertilize the seeds from the pistil. Not all pollen can make it to the pistil. It's the same as animals producing millions of sperms although only one is needed for fertilization.</span>

5 0

3 years ago

A substance that produces hydroxide ions when placed in water is a(n) _____.

bekas [8.4K]

Answer: A substance that produces hydroxide ions when placed in water is base.

Explanation:

Bases are the substance:

Which gives negatively charged hydroxide( $OH^-$ ) ions in aqueous solution.

Which have pH value ranging from 7 to 14.

$BOH(aq)\rightarrow B^+(aq)+OH^-(aq)$

Where as acid gives positively charged hydronium ion( $H^+$ ) in aqueous solution.

7 0

3 years ago

Read 2 more answers

Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose

Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution = 101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0

3 years ago

Which of these is an example of a metaphor?

emmainna [20.7K]

Answer:

a i think

Explanation:

because it was the only one that compared something to another

5 0

4 years ago