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Alina [70]
3 years ago
9

OT protons (d) (a) and (b)

Chemistry
2 answers:
insens350 [35]3 years ago
6 0
<h2>b is the correct answer</h2>

according In my course I studying it all

Dafna1 [17]3 years ago
3 0

Answer:

A.

Explanation:

sana makatulong sayo

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A chemist reacted 57.50 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is show
pantera1 [17]
(On my left) (On my right side)
Na: 1. Na:1
Cl:2. Cl:1

Na:1 x 2 =2
Na:1 x 2=2
Cl: 1 x 2 = 2

Answer:
2Na + Cl2 -> 2NaCl
5 0
2 years ago
A light wave has frequency of 4.5 * 10^19 Hz. How would this number appear on a scientific calculator? a. 4.E195 b. 19E4.5 c. 4.
scoray [572]

Answer:

B

Explanation:

3 0
3 years ago
The recommended maintenance dose of penicillin for children is 1.0 mg/kg/hr by injection. Of 10 mL of a 25 mg/mL solution of pen
SOVA2 [1]

This problem is providing us with the recommended maintenance dose of penicillin for children as 1.0 mg/kg/hr by injection. Thus, the delivery rate for a 40-pound child is required, if 10 mL of a 25 mg/mL solution of penicillin is added to a 100-mL bottle of saline. At the end, the result is 8.0 mL/hr:

<h3>Dimensional analysis:</h3>

In chemistry, dimensional analysis allows us to obtain a specific result given relevant information about it. Although a formula is not always provided, one can use the units as a reference for the calculations.

For example, this problem asks for the rate, in mL/hr, at which a child gets this dose, so the first step will be to get the mass of the child in kilograms:

40 lb*\frac{0.4536kg}{1lb}= 18.144kg

Next, we calculate the rate at which the penicillin is delivered to this child:

1.0\frac{mg}{kg*hr} *18.144kg=18.144\frac{mg}{hr}

After that, we calculate the total mass of penicillin that is delivered:

10mL*25\frac{mg}{mL} =250 mg

And get the new concentration once it is diluted to 100 mL:

\frac{250mg}{10mL+100mL}=2.27\frac{mg}{mL}

And finally, we combine the mg/hr with the mg/mL to get the result in mL/hr as required:

18.144\frac{mg}{hr} *\frac{1mL}{2.27mg}\\ \\=8.0\frac{mL}{hr}

Learn more about dimensional analysis: brainly.com/question/10874167

5 0
2 years ago
A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513
igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is:  N₂O₄(g)  ⇆  2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

              2NO₂ (g)   ⇆   N₂O₄(g)      

Initially   2.20 mol              -

React          x                      x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq       (2.20-x) / 3.50L     (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) /  [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0  → Quadratic formula

a = 0.2933 ;  b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50  = 0.0971 M

8 0
3 years ago
2. The air pressure inside a submarine is 0.56 atm. What would be the pressure in<br> mmHg?
Soloha48 [4]
The answer would be 425.599 because 1 ATM is 760 mmHg.
8 0
3 years ago
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