Answer:
t = 12,105.96 sec
Explanation:
Given data:
weight of spacecraft is 2000 kg
circular orbit distance to saturn = 180 km
specific impulse = 300 sec
saturn orbit around the sun R_2 = 1.43 *10^9 km
earth orbit around the sun R_1= 149.6 * 10^ 6 km
time required for the mission is given as t
where
is gravitational parameter of sun = 1.32712 x 10^20 m^3 s^2.
t = 12,105.96 sec
Answer:4.93 m/s
Explanation:
Given
height to reach is (h )1.24 m
here Let initial velocity is u
using equation of motion
here Final Velocity v=0
a=acceleration due to gravity
u=4.93 m/s
Answer:
0.74 m/s
Explanation:
given,
time taken by the ramp to cover cliff , t = 64 s
acceleration = 0.37 m/s²
distance traveled by the belt
Clifford is moving with constant acceleration
...(1)
initial velocity is equal to zero
........(2)
equating equation (1) and (2)
Speed of the belt is equal to 0.74 m/s