Question

A Carnot engine operates between reservoirs at 600 and 300 K. If the engine absorbs 100 J per cycle at the hot reservoir, what is its work output per cycle?

Answer 1

Answer:

W =50 J

Explanation:

given data:

T_h=600 k

T_L=300 k

Q_h=100 J

required:

W=??

solution:

║W║=║Q_h║(1-T_L/T_h)

        =50 J

Answer 2

Answer:

50J

Explanation:

For a Carnot engine, the work output (W) per cycle is given by;

W = Q (1 - $\frac{T_{C} }{T_{H}}$)          ----------------(i)

Where;

Q = heat absorbed by the engine per cycle

$T_{C}$ = Temperature of the colder reservoir

$T_{H}$ = Temperature of the hotter reservoir

From the question;

Q = 100J

$T_{C}$ = 300K

$T_{H}$ = 600K

Substitute these values into equation (i) as follows;

W = 100 (1 - $\frac{300 }{600}$)

W = 100 (1 - $\frac{1}{2}$)

W = 100 ($\frac{1}{2}$)

W = 50 J

Therefore, the work output per cycle is 50J