A Carnot engine operates between reservoirs at 600 and 300 K. If the engine absorbs 100 J per cycle at the hot reservoir, what i
2 answers:
<h2>Answer:</h2>
50J
<h2>Explanation:</h2>For a Carnot engine, the work output (W) per cycle is given by;
W = Q (1 - ) ----------------(i)
Where;
Q = heat absorbed by the engine per cycle
= Temperature of the colder reservoir
= Temperature of the hotter reservoir
<em>From the question;</em>
Q = 100J
= 300K
= 600K
<em>Substitute these values into equation (i) as follows;</em>
W = 100 (1 - )
W = 100 (1 - )
W = 100 ()
W = 50 J
Therefore, the work output per cycle is 50J
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Explanation:
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