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Answer:
volume of biological sludge = 28.566 m³ per day
Explanation:
given data
mass of solid = 7240 kg/day
initial moisture content = 78%
solution
here percentage of solid will be
% of solid = 100 - initial moisture content
% of solid = 100 - 78 = 22 %
so that
mass of sludge produced = kg per day
put her value
mass of sludge produced = kg
mass of sludge produced = 32909.09 kg
so
specific gravity of sludge =
and as we know that
= 1.152
so that
density of sludge = S sludge × density of water
density of sludge = 1.152 × 1000
density of sludge = 1152 kg/m³
so that
volume of biological sludge =
volume of biological sludge =
volume of biological sludge = 28.566 m³ per day