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Bas_tet [7]
3 years ago
7

An experimenter places a piece of solid metal weighing 255g into a graduated cylinder which she then fills with mercury. After w

eighing the cylinder and its contents, she removes the solid and tops of the cylinder with mercury. The cylinder and its contents weigh 101g less than before. The density of Hg is 13.6g/cm^3 . What is the density of the solid metal
Chemistry
1 answer:
damaskus [11]3 years ago
7 0

Answer: the density of the solid metal is 22.5176 g/cm

Explanation:

Given that;

mass of solid metal = 255 g

the cylinder and its contents weigh 101g less than before

also given that density of mercury = 13.6 g/cm³    

Volume of the solid metal = volume of mercury which was absent in the first weighing

so let volume = Vcm³

Mass of mercury which was absent in the first weighing = density × volume

= 13.6 g/cm³  × Vcm³ = 13.6V g

now since the cylinder and its contents weigh 101g less than before,

it means the difference in mass between the solid and metal and the mass of mercury is equal to 101 g

so

255 - 13.6V g = 101g

13.6V g = 255 g - 101 g

13.6V  = 154

V = 154 /  13.6

V = 11.3245 cm³

Now Density of solid metal will be;

⇒ mass / volume

= 255 / 11.3245

= 22.5176 g/cm

Therefore, the density of the solid metal is 22.5176 g/cm

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How many atoms are in 2.10 g of K? molar mass of K=39.10g/mole.
Alborosie

Answer:

<h3>The answer is option B</h3>

Explanation:

To calculate the number of atoms we must first calculate the number of moles

Molar mass = mass / number of moles

number of moles = mass / Molar mass

Molar mass (K) = 39.10mole

mass = 2.10g

number of moles = 2.10/ 39.10

= 0.0537mol

After that we use the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10^23 entities

Number of K atoms is

N = 0.0537 × 6.02 × 10^13

<h3>N = 3.23×10^22 atoms of K</h3>

Hope this helps you.

5 0
3 years ago
The following three equations represent reactions done in this lab exercise. Classify each reaction by their type. Note there ma
gulaghasi [49]

Answer: 1. Cu(s)+4HNO_3(aq)rightarrow Cu(NO_3)_2(aq)+2NO_2(g)+2H_2O(l) : oxidation reduction

2. Cu(NO_3)_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaNO_3(aq) : precipitation

3. CuO(s)+2HCl(aq)\rightarrow CuCl_2(aq)+H_2O(l) : Double displacement

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Cu(s)+4HNO_3(aq)rightarrow Cu(NO_3)_2(aq)+2NO_2(g)+2H_2O(l)

Double displacement reaction is defined as the reaction where exchange of ions takes place. Double displacement reaction in which one of the product remain in solid form are represented by (s) after their chemical formulas. Such double displacement reaction are called as precipitation reaction.

Cu(NO_3)_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaNO_3(aq)

Double displacement reaction is defined as the reaction where exchange of ions takes place.

CuO(s)+2HCl(aq)\rightarrow CuCl_2(aq)+H_2O(l)

Single displacement reaction is defined as the reaction where more reactive element displaces a less reactive element from its chemical reaction.

Decomposition reaction is defined as the reaction where a single substance breaks down into two or more simpler substances.

Synthesis/Combination reaction is defined as the reaction where substances combine in their elemental state to form a single compound.

6 0
3 years ago
Diamond has a density of 3.513 g/cm³. The mass of diamonds is often measured in "carats," where 1 carat equals 0.200
Gennadij [26K]

The volume of a 1.86-carat diamond in cubic centimeters is 0.106 cm³

Given,

The density of a diamond is  3.513 g/cm³.

We have to find out the volume of a 1.86-carat diamond in cubic centimeters.

Convert the units of the diamond from carat to grams, we have:

(1.86 carats) x (0.200 g / 1 carat) = 0.372 g

The volume of the diamond is obtained by dividing the mass by the density, therefore using the formula, we get

                            v = m / d

                            v = 0.372 g / (3.51 g/cm³) = 0.1059 cm³

                       or, v = 0.106 cm³ (approx)

Therefore, the volume of a 1.86-carat diamond is approximately 0.106 cm³.

To learn more about the volume, visit: brainly.com/question/1578538

#SPJ9

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2 years ago
Which compound contains both sigma and pi bonds
Misha Larkins [42]
Any compound with multiple covalent bonds
6 0
3 years ago
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Cohesion holds hydrogen bonds together to create surface tension on water. Since water is attracted to other molecules, adhesive forces pull the water toward other molecules.
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4 years ago
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