Given the data from the question, reaction 2 is 2.83 times faster compared to reaction 1
<h3>Data obtained from the question</h3>
- Molarity of reaction 1 (R₁) = 0.180 mol/L
- Molarity of reaction 2 (R₂) = 0.510 mol/L
- Comparison =?
<h3>How to determine the comparison of reaction 2 to reaction 1</h3>
We can determine how many times faster is reaction 2 to reaction by doing the following:
R₂ / R₁ = 0.510 / 0.180
R₂ / R₁ = 2.83
Cross multiply
R₂ = 2.83 × R₁
From the above illustration, we can see that reaction 2 is 2.83 times faster than reaction 1
Learn more about Graham's law of diffusion:
brainly.com/question/14004529
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Answer:
???
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
u make subject of fomula x then divide by
G(x)/f(x) will be simplified to (x+3)(x-3)/2-x^1/2,
which will give you [0,4) ∪(4, ∞).
Choice B
