The car will gain new momentum if it's velocity is doubled or tripled.
Answer:........u are so sweet
Effort force
Explanation:
When the potion of fulcrum and weight is changed, the mechanical advantage changes.Increasing the distance between the fulcrum and the effort, there is a proportion increase in effort required to lift a load.The ration of the distance from the fulcrum to the position of input and output application gives the mechanical advantage in levers when losses due to friction are not considered.
Learn More
Mechanical advantage in Levers : brainly.com/question/11600677
Keywords : Levers, fulcrum, position
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Answer:
Explanation:
Given
Distance to grandmother's house=100 mi
it is given that during return trip Julie spend equal time driving with speed 30 mph and 70 mph
Let Julie travel x mi with 30 mph and 100-x with 70 mph
![\frac{x}{30}=\frac{100-x}{70}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B30%7D%3D%5Cfrac%7B100-x%7D%7B70%7D)
x=30 mi
Therefore
Julie's Average speed on the way to Grandmother's house![=\frac{100}{\frac{50}{30}+\frac{50}{70}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B100%7D%7B%5Cfrac%7B50%7D%7B30%7D%2B%5Cfrac%7B50%7D%7B70%7D%7D)
=42 mph
On return trip
![=\frac{100}{2\frac{30}{30}}=50 mph](https://tex.z-dn.net/?f=%3D%5Cfrac%7B100%7D%7B2%5Cfrac%7B30%7D%7B30%7D%7D%3D50%20mph)
Answer:
a)
1.35 kg
b)
2.67 ms⁻¹
Explanation:
a)
= mass of first body = 2.7 kg
= mass of second body = ?
= initial velocity of the first body before collision = ![v](https://tex.z-dn.net/?f=v)
= initial velocity of the second body before collision = 0 m/s
= final velocity of the first body after collision =
using conservation of momentum equation
![m_{1} v_{1i} + m_{2} v_{2i} = m_{1} v_{1f} + m_{2} v_{2f}\\(2.7) v + m_{2} (0) = (2.7) (\frac{v}{3} ) + m_{2} v_{2f}\\(2.7) (\frac{2v}{3} ) = m_{2} v_{2f}\\v_{2f} = \frac{1.8v}{m_{2}}](https://tex.z-dn.net/?f=m_%7B1%7D%20v_%7B1i%7D%20%2B%20m_%7B2%7D%20v_%7B2i%7D%20%3D%20m_%7B1%7D%20v_%7B1f%7D%20%2B%20m_%7B2%7D%20v_%7B2f%7D%5C%5C%282.7%29%20v%20%2B%20m_%7B2%7D%20%280%29%20%3D%20%282.7%29%20%28%5Cfrac%7Bv%7D%7B3%7D%20%29%20%2B%20m_%7B2%7D%20v_%7B2f%7D%5C%5C%282.7%29%20%28%5Cfrac%7B2v%7D%7B3%7D%20%29%20%3D%20m_%7B2%7D%20v_%7B2f%7D%5C%5Cv_%7B2f%7D%20%3D%20%5Cfrac%7B1.8v%7D%7Bm_%7B2%7D%7D)
Using conservation of kinetic energy
![m_{1} v_{1i}^{2}+ m_{2} v_{2i}^{2} = m_{1} v_{1f}^{2} + m_{2} v_{2f}^{2} \\(2.7) v^{2} + m_{2} (0)^{2} = (2.7) (\frac{v}{3} )^{2} + m_{2} (\frac{1.8v}{m_{2}})^{2} \\(2.7) = (0.3) + \frac{3.24}{m_{2}}\\m_{2} = 1.35](https://tex.z-dn.net/?f=m_%7B1%7D%20v_%7B1i%7D%5E%7B2%7D%2B%20m_%7B2%7D%20v_%7B2i%7D%5E%7B2%7D%20%3D%20m_%7B1%7D%20v_%7B1f%7D%5E%7B2%7D%20%2B%20m_%7B2%7D%20v_%7B2f%7D%5E%7B2%7D%20%5C%5C%282.7%29%20v%5E%7B2%7D%20%2B%20m_%7B2%7D%20%280%29%5E%7B2%7D%20%3D%20%282.7%29%20%28%5Cfrac%7Bv%7D%7B3%7D%20%29%5E%7B2%7D%20%2B%20m_%7B2%7D%20%28%5Cfrac%7B1.8v%7D%7Bm_%7B2%7D%7D%29%5E%7B2%7D%20%5C%5C%282.7%29%20%3D%20%280.3%29%20%2B%20%5Cfrac%7B3.24%7D%7Bm_%7B2%7D%7D%5C%5Cm_%7B2%7D%20%3D%201.35)
b)
= mass of first body = 2.7 kg
= mass of second body = 1.35 kg
= initial velocity of the first body before collision = 4 ms⁻¹
= initial velocity of the second body before collision = 0 m/s
Speed of the center of mass of two-body system is given as
ms⁻¹