What are the factors of x2 - 144? and

Mathematics

1 answer:

likoan [24]3 years ago

3 0

Answer:

Step-by-step explanation:

x² - 144 = x² - 12²

= (x +12)(x - 12)

a² - b² = (a + b)(a-b)

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Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

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