The cost of the 9th item is $3.94
Since the mean cost for the 9 items in his bag was $2.71. Then, the total cost will be: = 9 × $2.71 = $24.39
In order to get the price of the 9th item, we have to calculate the price of all the 8 items given which will be:
$2.01 + $2.20 + $2.68 + $3.59 + $3.12 + $1.64, + $1.75 + $3.46 = $20.45
Therefore, the cost of the 9th item will be:
= $24.39 - $20.45
= $3.94
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<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.
To solve our given problem, we will divide total volume of wax by volume of one candle.
Volume of each candle will be equal to volume of sphere.
, where r represents radius of sphere.
We know that radius is half the diameter, so radius of each candle will be
cm.



Now we will divide 70,650 cubic cm of wax by volume of one candle.



Therefore, 40 candles can be made from 70,650 cubic cm of wax.
Slope intercept: y = mx + b
Plug in the slope
Y = -3/2x + b
Plug in the point
-9 = -3/2(10) + b, b = 6
Equation: y = -3/2x + 6