Given that <span>sample a has a higher melting point than sample
b. Therefore, sample a is a longer chain of a </span><span>fatlike solid substance. It could also be that the bonds present in sample a is much stronger which will require more energy to break. Hope this answers the question.</span>
Answer:
Explanation:
1. Gather all the information in one place.
S + 3F₂ ⟶ SF₆
n/mol: 6 15
They have given us the amounts of two reactants and asked us to calculate the amount of product. This is a limiting reactant problem.
2. Calculate the moles of SF₆ you can obtain from each reactant
From S:
From F₂:
SF₆ is the limiting reactant, because it gives fewer moles ( 5 mol) of SF₆.
The reaction can form 5 mol of SF₆.
Answer:
1. Rearranged
2. Different
3. The same after the reaction.
Explanation:
B.) Unsaturated... Because it can take on more.
If it can't take on more, it's saturated. If it takes more than it can hold, it's supersaturated.