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-BARSIC- [3]
3 years ago
12

Cloudy nights can be warmer than clear nighys because clouds trap heat

Physics
1 answer:
Rasek [7]3 years ago
4 0
<span>Is it true that nighttime air temperatures on a cloudy night are lower than they would be on a clear night?</span>
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a trampoline launches a 50kg person 2m into the air. if the springs push with 1960N of force, how much displacement was there in
Lina20 [59]

Answer: 0.5 m

Explanation:

Given

Mass of the person is m=50\ kg

Trampoline launches the person into the air up to height of h=2\ m

Force experience by springs is F=1960\ N

Here, the work done on displacing the springs is equivalent to the Potential energy acquired by the person i.e.

\Rightarrow F\cdot x=mgh\quad [\text{x=displacement of the trampoline}]\\\\\text{Insert the values}\\\\\Rightarrow x=\dfrac{50\times 9.8\times 2}{1960}\\\\\Rightarrow x=\dfrac{980}{1960}\\\\\Rightarrow x=0.5\ m

6 0
3 years ago
Read 2 more answers
Describe how the forces of gravity and friction affect the motion that occurs as you write on this page.
Zinaida [17]

Answer:

Friction is a force that slows down the motion of a moving object. ... Eventually, friction and gravity will work together to stop the motion of the slide. Gravity is a force that pulls two objects toward each other because of their mass. Mass is the measurement of the amount of material (matter) that makes up an object.

6 0
2 years ago
A Carnot engine operates between reservoirs at 600 and 300 K. If the engine absorbs 100 J per cycle at the hot reservoir, what i
PIT_PIT [208]

Answer:

W =50 J

Explanation:

given data:

T_h=600 k

T_L=300 k

Q_h=100 J

required:

<em>W=??</em>

<u>solution:</u>

║W║=║Q_h║(1-T_L/T_h)

        =50 J

7 0
3 years ago
Read 2 more answers
When a sinusoidal wave with speed 20 m/s , wavelength 35 cm and amplitude of 1.0 cm passes, what is the maximum speed of a point
vova2212 [387]

To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion

From the definition we know that the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

v = Velocity \rightarrow 20m/s

\lambda = Wavelength \rightarrow 35*10^{-2}m

Therefore the frequency would be given as

f = \frac{20}{35*10^{-2}}

f = 57.14Hz

The frequency is directly proportional to the angular velocity therefore

\omega = 2\pi f

\omega = 2\pi *57.14

\omega = 359.03rad/s

Now the maximum speed from the simple harmonic movement is given by

V_{max} = A\omega

Where

A = Amplitude

Then replacing,

V_{max} = (1*10^{-2})(359.03)

V_{max} = 3.59m/s

Therefore the maximum speed of a point on the string is 3.59m/s

8 0
4 years ago
This problem has been solved!See the answerCommunication with submerged submarines via radio waves is difficult because seawater
mash [69]

Answer:

4000 km

Explanation:

as we know velocity of electromagnetic wave is c

c = 3 * 10^8 m/s

frequency  given (f) = 76 Hz

wavelength ?

using

c =fλ

λ =   \frac{c}{f}

λ =  \frac{3 * 10^8}{76}  ≈4000 km

 so final answer λ = 4000km

8 0
3 years ago
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