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3 years ago

15

Cindy exerts a force of 40 N and moves a chair 6 m. Her brother and he pushes a different chair for 6 m while exerting a force o

f 30 N. Andy does: more, less work than Cindy. The difference of their amounts of work is: 20, 40, 60, or 180 Nm.

1 answer:

Lostsunrise [7]3 years ago

6 0

Wa = F*d = 240J
Wb = 180 J

Andy does less work
Difference is 60J

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A 0.500-nm x-ray photon is deected through 134 in a Compton scattering event. At what angle (with respect to the incident beam)

natita [175]

Answer:

The angle of recoil electron with respect to incident beam of photon is 22.90°.

Explanation:

Compton Scattering is the process of scattering of X-rays by a charge particle like electron.

The angle of the recoiling electron with respect to the incident beam is determine by the relation :

$\cot\phi = (1+\frac{hf}{m_{e}c^{2} })\tan\frac{\theta }{2}$ ....(1)

Here ∅ is angle of recoil electron, θ is the scattered angle, h is Planck's constant, $m_{e}$ is mass of electron, c is speed of light and f is the frequency of the x-ray photon.

We know that, f = c/λ ......(2)

Here λ is wavelength of x-ray photon.

Rearrange equation (1) with the help of equation (1) in terms of λ .

$\cot\phi = (1+\frac{h}{m_{e}c\lambda })\tan\frac{\theta }{2}$

Substitute 6.6 x 10⁻³⁴ m² kg s⁻¹ for h, 9.1 x 10⁻³¹ kg for $m_{e}$ , 3 x 10⁸ m/s for c, 0.500 x 10⁻⁹ m for λ and 134° for θ in the above equation.

$\cot\phi = (1+\frac{6.6\times10^{-34} }{9.1\times10^{-31}\times3\times10^{8}\times0.5\times10^{-9} })\tan\frac{134 }{2}$

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3 years ago

Gravity pushes objects away from each other TRUE OR FALSE

e-lub [12.9K]

Answer:

false

Explanation:

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2 years ago

15. If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the

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The final combined velocity after the collision is 20.2 m/s

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We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two car and of the truck must be conserved before and after the collision.

This means that we can write the following equation:

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where:

$m_1 = 800 kg$ is the mass of the sport car

$u_1 = 13.0 m/s$ is the initial velocity of the car (taking its direction as positive direction)

$m_2 = 1200 kg$ is the mass of the truck

$u_2 = 25.0 m/s$ is the initial velocity of the truck

$v$ is the final combined velocity of the car and the truck, after the collision

Re-arranging the equation and substituting the values, we find the velocity after the collision:

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Learn more about momentum here:

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3 years ago

When a 10 V battery is connected to a resistor, 5 A of current flows through the resistor. What is the resistor's value?

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Given data

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1 year ago

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mamaluj [8]

Answer:

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Solve using the quadratic formula.

$x=\frac{-y+\sqrt{y^2+4rt} }{2r}$

$x=\frac{-y-\sqrt{y^2+4rt} }{2r}$

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3 years ago

Read 2 more answers