Answer:
Expected number of hours before the the group exits the building = E[Number of hours] = 3.2 hours
Step-by-step explanation:
Expected value, E(X) is given as
E(X) = Σ xᵢpᵢ
xᵢ = each variable
pᵢ = probability of each variable
Let X represent the number of hours before exiting the building taking each door. Note that D = Door
D | X | P(X)
1 | 3.0 | 0.2
2 | 3.5 | 0.1
3 | 5.0 | 0.2
4 | 2.5 | 0.5
E(X) = (3×0.2) + (3.5×0.1) + (5×0.2) + (2.5×0.5) = 3.2 hours
Hope this Helps!!!
I hope it's clear enough.
V=(4pr^3)/3 if r=12
V=2304p in^3
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.
To find the mean absolute deviation, we first find the mean. Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5
Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
5+2+2+2+1+1+5+4+3+1 = 26
We now divide this by the number of data points:
26/10 = 2.6
This is a measure of how much each bag of candy varies from the mean.
Answer:
$6261.61
Step-by-step explanation:
The solution to the differential equation is the exponential function ...
A(t) = 5000e^(0.0225t)
We want the account value after 10 years:
A(10) = 5000e^(0.225) = 6261.61
The value of the account after 10 years will be $6,261.61.
_____
The rate of change equation basically tells you that interest is compounded continuously. After working interest problems for a while you know the formula for that is the exponential formula A = A0·e^(rt).
Or, you can solve the differential equation using separation of variables:
dA/A = 0.0225dt
ln(A) = 0.0225t +C . . . . integrate
A(t) = A0·e^(0.0225t) = 5000·e^(0.0225t) . . . . solution for A(0) = 5000
