Question

During a safety test, a car hits a wall and stops in 0.55 s. The net force on the car is 6500 N during the collision. What is the magnitude of the change in momentum of the car? Round answer to two significant digits. kg m

Answer 1

Answer:

ΔP = 3600 kg m/s.

Explanation:

Change in momentum (ΔP) of the car is the amount of impulse on it. Impulse (I) can be define as the product of force and the time at which it acts.

i.e I = ΔP

But, I = Ft

Ft = ΔP

ΔP = 6500 x 0.55

     = 3575 Ns

     = 3600 kg m/$s^{2}$ x s

ΔP = 3600 kg m/s

The magnitude of the change in momentum of the car is 3600 kgm/s.