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3 years ago

Which of these correctly describes the energy that makes the carousel turn

Chemistry

1 answer:

Dmitrij [34]3 years ago

8 0

Answer:

Explanation:

A carousel can be made to rotate using different sources of energy. One may decide to use electric energy, manual effort, water energy or heat energy as in a candle carousel.

When the candle is lit, heat energy is supplied and warm air rises heating up the air near the carousel eventually causing it to start rotating.

Hence heat from the candle leads to a current of warm air that rises up, causing the carousel to start rotating.

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What effect does increasing the concentration of a dissolved solute have on each of the colligative properties?

Igoryamba

Answer:

If we increase the concentration of a dissolved solute, the solution would have a vapor pressure so much low, the boiling temperature for the solution will be so high, freezing point for the solution will be so much low and the osmotic pressure will be higher.

Colligative properties always depends on dissolved particles (solute)

Explanation:

These are the colligative properties

- Vapor pressure lowering

ΔP = P° . Xm

Vapor pressure of pure solvent - Vapor pressure of solution.

If we add more solute, it would raise the Xm, so the solution would have a vapor pressure so much low.

Vapor pressure pure solvent - Vapor pressure solution ↑ = P° . Xm ↑

- Boiling point elevation

ΔT = Kb . m

When we add more solute, we are increasing the molality.

↑T° boiling of solution - T° boiling pure solvent = Kf . m ↑

Boiling temperature for the solution will be so high.

- Freezing point depression

When we add more solute, we are increasing the molality.

ΔT = Kf . m

T° fussion of pure solvent - ↓T° fussion of solution = Kf . m↑

Freezing point for the solution will be so much low.

- Osmotic pressure

π = M . R . T

When we add solute, molarity is increasing. Therefore the osmotic pressure will be higher.

π↑ = M↑ . R . T

7 0

4 years ago

Which of the following forms of oxygen can undergo disproportionation?

Akimi4 [234]

<span>disproportionation is a type of redox reaction in which an element can undergo both oxidation and reduction.

Let's take a look at the choices:
First we have the oxide ion. Oxide ion has a charge of -2 which is the lowest charge that an oxygen atom can have. Therefore, an oxide ion cannot be further reduced, so this choice is not correct.
Next we have the peroxide ion. The oxygen has a charge of -1 which means it can be further reduced. So, this choice is acceptable
Last but not least, we have the superoxide ion. The oxygen has a charge of -1/2 which means it can be further reduced. So, this choice is also acceptable.

Based on this, we have two accepted choices which are b and c.</span>

5 0

3 years ago

Suppose you have a dozen carbon atoms, a dozen gold atoms, and a dozen iron atoms. Even though you have the same number of each,

mixer [17]

Answer:

By weight they have the same mass, but the number of atoms is different

Explanation:

3 0

4 years ago

Read 2 more answers

In the reaction MgCl2 + 2KOH Mg(OH)2+ 2KCI, if 3 moles MgCh are added to 4 moles KOH, what determines how much Mg(OH)2 is made?

gulaghasi [49]

Answer:-

KOH determines how much Mg(OH)2 is made.

2 mol of Mg(OH)2 formed

Explanation:-

The balanced equation is

MgCl2 + 2KOH --> Mg(OH)2+ 2KCI,

From seeing the coefficients we notice

2 mol of KOH reacts with 1 mol of MgCl2

4 mol of KOH reacts with 1 x 4 / 2 = 2 mol of MgCl2

3 moles of MgCl2 was added but only 2 mol react.

So we see there is excess MgCl2 .

Hence KOH is the limiting reactant.

So KOH determines how much Mg(OH)2 is made.

We see from the balanced chemical equation,

2 mol of KOH gives 1 mol of Mg(OH)2.

4 mol of KOH will give 1 x 4 /2 = 2 mol of Mg(OH)2.

7 0

3 years ago

Hi! I could use some help, I need to turn this in today

TiliK225 [7]

Explanation:

The nomenclature of ionic compounds is given by:

1. Positive is written first. And if the metal atom has various oxidation states then its oxidation state is to be mentioned in brackets with help of roman numbers

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

1.) : Calcium chloride (Correct)

In the given compound, calcium has oxidation state of +2 and chlorine has oxidation state of -1.The name is correct.

2.) : Copper (II) oxide (Incorrect)

In the given compound,copper has the oxidation state of +1 and oxygen has oxidation state of -2.So ,the correct name will be Copper (I) oxide.

3.) : Lead (II) sulfide (Incorrect)

In the given compound, lead has the oxidation state of +4 and sulfur has oxidation state of -2. So ,the correct name will be Lead (IV) sulfide.

3 0

3 years ago