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Westkost [7]
3 years ago
8

In ΔNOP, o = 660 inches, p = 510 inches and ∠N=152°. Find the length of n, to the nearest inch.

Mathematics
1 answer:
VikaD [51]3 years ago
7 0

Answer:

1136

Step-by-step explanation:

deltamath

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Use &lt;,&gt;,or= to compare the ratios 36 ? 6 <br> 60 10
katen-ka-za [31]

Answer:

36/60 =6/10

Step-by-step explanation:

36/60 = 0.6

6/10=0.6

4 0
3 years ago
What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po
emmasim [6.3K]
\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS
\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS
\displaystyle\iint_\sigma\mathbf F\cdot\left(\frac{\mathbf r_u\times\mathbf r_v}{\|\mathbf r_u\times\mathbf r_v\|}\right)\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dA
\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k
\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j

The cross product is

\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j

So, the flux is given by

\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA
\displaystyle\int_0^5\int_0^{2\pi}(-e^{-\sin v}\cos v+2\sin^2v)\,\mathrm dv\,\mathrm du
\displaystyle-5\int_0^{2\pi}e^{-\sin v}\cos v\,\mathrm dv+10\int_0^{2\pi}\sin^2v\,\mathrm dv
\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv

where t=-\sin v in the first integral, and the half-angle identity is used in the second. The first integral vanishes, leaving you with

\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi
5 0
3 years ago
What is the equation for the black line?
BARSIC [14]
-3 and 5..................
8 0
3 years ago
Classify the triangle by its angles.
dedylja [7]

Answer:

29°: Acute 90°: Right 61°: Acute

Step-by-step explanation:

If an angle is less than 90 degrees, it is acute. If it is greater than 90 degrees, it is obtuse. If it is exactly 90 degrees, it is right.

7 0
3 years ago
Read 2 more answers
Is calculating his expenses from his work trip to San Francisco. Below is the expense log he kept while traveling.
Alika [10]

Answer:

D

Step-by-step explanation:

379.00 - 15.00 + 154.00 x 3 + 65.00 + 13.00 = 904

0.55 x 63 = 34.65

34.65 + 904 = 938.65

5 0
3 years ago
Read 2 more answers
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