Answer:
3.71 m/s
Explanation:
From the law of conservation of linear momentum, since we are neglecting minor energy losses due to friction then we can express it as since all the potential energy is transformed to kinetic energy
Making v the subject of the formula then and here m is the mass of the block, g is acceleration due to gravity, h is the height. Substituting 0.7 m for h and 9.81 for g then we obtain that
Answer:
The answer to the question is
The distance d, which locates the point where the light strikes the bottom is 29.345 m from the spotlight.
Explanation:
To solve the question we note that Snell's law states that
The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction
n₁sinθ₁ = n₂sinθ₂
y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and
θ₁ = 14.511 °
n₁ = 1.0003 = refractive index of air
n₂ = 1.33 = refractive index of water
Therefore sinθ₂ = =
= 0.1885 and θ₂ = 10.86 °
Since the water depth is 4.0 m we have tanθ₂ = or x₂ =
=
= 20.845 m
d = x₂ + 8.5 = 20.845 m + 8.5 m = 29.345 m.
The velocity of the wave on the string is given by
Solving the above equation,
The frequency of the wave and wave length is
The velocity is
Substituting numerical values,
The length of the string is
Answer:
103063860 Pa
Explanation:
= Density of seawater = 1030 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Depth at which pressure is being measured = 10.2 km
The gauge pressure is given by
Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa