All categories

3 years ago

The equation for one of the reactions in the process of turning iron ore into the metal is

Chemistry

1 answer:

Leona [35]3 years ago

7 0

Answer:

2100g or 2.1kg

Explanation:

Based on the equation given,

One mole of Fe2O3 gives two moles of Fe

Molar mass for Fe2O3 is 160g/mol

Molar mass for two Fe is 112g/mol

Convert 3kg to gram

3×1000=3000grams

160g of Fe2O3-112 g of Fe

3000g of Fe2O3-xg of Fe

Xg=3000×112/160

Xg=2100g

To convert to kg

2100/1000=2.1kg

Mass of Fe is 2.1kg

You might be interested in

Why is space cold ???

Norma-Jean [14]

Because the space is ultimate thermos.

4 0

2 years ago

Closest noble gas to neon?

Nataly [62]

Hi!

I'm not entirely sure about this so I'm sorry if I'm wrong but I think it would be helium.

Again in not entirely sure but i hope this helped you, i hope you have a great day, afternoon, or night!

7 0

3 years ago

Read 2 more answers

Convert 3.30 g of copper (II) hydroxide Cu(OH)2 to molecules.

ratelena [41]

Answer:

0.18× 10²³ molecules

Explanation:

Given data:

Mass of copper hydroxide = 3.30 g

Number of molecules = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 3.30 g/97.56 g/mol

Number of moles = 0.03 mol

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.03 mol × 6.022 × 10²³ molecules / 1mol

0.18× 10²³ molecules

6 0

2 years ago

The atoms in a copper bar are held together by metallic bonding. What would happen you ran over a copper bar with a car? It woul

ludmilkaskok [199]

The answer is D.

<em>Hope this helps!</em>

4 0

3 years ago

Read 2 more answers

Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe

Illusion [34]

Answer:

a. Kp=1.4

$P_{A}=0.2215 atm$

$P_{B}=0.556 atm$

b.Kp=2.0 * 10^-4

$P_{A}=0.495atm$

$P_{B}=0.00995 atm$

c.Kp=2.0 * 10^5

$P_{A}=5*10^{-6}atm$

$P_{B}=0.9999 atm$

Explanation:

For the reaction

A(g)⇌2B(g)

Kp is defined as:

$Kp=\frac{(P_{B})^{2}}{P_{A}}$

The conditions in the system are:

A B

initial 0 1 atm

equilibrium x 1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.

Replacing these values in the expression for Kp we get:

$Kp=\frac{(1-2x)^{2}}{x}$