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3 years ago

The equation for one of the reactions in the process of turning iron ore into the metal is

Chemistry

1 answer:

Leona [35]3 years ago

7 0

Answer:

2100g or 2.1kg

Explanation:

Based on the equation given,

One mole of Fe2O3 gives two moles of Fe

Molar mass for Fe2O3 is 160g/mol

Molar mass for two Fe is 112g/mol

Convert 3kg to gram

3×1000=3000grams

160g of Fe2O3-112 g of Fe

3000g of Fe2O3-xg of Fe

Xg=3000×112/160

Xg=2100g

To convert to kg

2100/1000=2.1kg

Mass of Fe is 2.1kg

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The fifth element in group 7 in astatine would you expect it to be gas, liquid, or solid? why?

Ymorist [56]

Answer:

solid

Explanation:

Melting and boiling points of Group 7 elements State at room temperature Room temperature is usually taken as being 25°C. At this temperature, fluorine and chlorine are gases, bromine is a liquid, and iodine and astatine are solids. There is therefore a trend in state from gas to liquid to solid as you go down the group.

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2 years ago

2.Which term best describes the processes that change rocks and mountains on Earth’s surface over time?

ArbitrLikvidat [17]

Answer:

B. weathering

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3 years ago

Which equation represents sublimation?<br> 2Al+3I=2AlI<br> HgCl=HgCl

AlexFokin [52]

I guess it is the second one but you missed the state symbols.

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3 years ago

formic acid, hcooh, is a weak acid with a ka equal to 1.8×10–4. what is the ph of a 0.0115 m aqueous formic acid solution?

kvasek [131]

The pH of a 0.0115 m aqueous formic acid solution is mathematically given as

pH=2.8424

This is further explained below.

<h3>What is the ph of a 0.0115 m aqueous formic acid solution?</h3>

Generally, the equation for the chemical equation is mathematically given as

HCOOH H^+ + HCOO

$\quad C-C \alpha \quad C \alpha$

$&k a=\frac{c^2 \alpha^2}{e(1-\alpha)}\\\\&K_a=\frac{c \alpha^2}{1-\alpha_4} \quad|\gg\rangle \alpha\\\\&K_a=c \alpha^2\\\\&\alpha=\sqrt{\frac{k a}{c}}\\\\&\alpha=\sqrt{\frac{1.8 \times 10^{-4}}{0.0115}}\\\\&\alpha=\sqrt{156: 527710^{-4}}\\\\&\alpha=\sqrt{1.565 \times 1 \sigma^2}\\\\&\alpha=1.25 \times 10^{-1}\\\\&\alpha=0.125\\$

$&\left[\mathrm{H}^{+}\right]=\mathrm{C \alpha}\\\\&=0.125 \times 0.0115\\\\&=1.4375 \times 10^{-9}\\\\&P=-\log \left[H^{+}\right]\\\\&=-\log \left[1.4375 \times 10^{-3}\right]\\\\&P H=2.8424$