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Natali5045456 [20]

2 years ago

15

Define 1 watt power?

1 answer:

Bumek [7]2 years ago

5 0

Answer:

A body is said to have power of 1 watt if it does work at the rate of 1 joule in 1 s. Watt is the SI unit of power. Other units of power include ergs per second, horsepower, metric horsepower or cheval vapeur (CV)), and foot-pounds per minute. The unit Watt is named after the scientist James Watt.

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A 1250 kg car is stopped at a traffic light. A 3550 kg truck moving at 8.33 m/s hits the car from behind. If bumpers lock, how f

Radda [10]

Answer:

the two vehicles will be moving at a speed of 6.16 m/s

Explanation:

This is a case of completely inelastic collision, therefore, the conservation of momentum can be written as:

$m_1\,v_1+m_2\,v_2=(m_1+m_2)\,v_f$

which given the information provided results into:

$m_1\,v_1+m_2\,v_2=(m_1+m_2)\,v_f\\(1250)\,(0)+(3550)\,(8.33)=(1250+3550)\,v_f\\29571.5=4800\,v_f\\v_f=6.16\,\,m/s$

7 0

3 years ago

You are designing a rotating metal flywheel that will be used to store energy. The flywheel is to be a uniform disk with radius

Gennadij [26K]

Answer:

t = 0.0735 m

Explanation:

Angular acceleration of the flywheel is given as

$\alpha = 3 rad/s^2$

now after t = 8 s the speed of the flywheel is given as

$\omega = \alpha t$

$\omega = 3 \times 8$

$\omega = 24 rad/s$

now rotational kinetic energy of the wheel is given as

$K = \frac{1}{2}I\omega^2$

$K = \frac{1}{2}(\frac{1}{2}mR^2)(24^2)$

$800 = \frac{1}{4}m(0.23)^2(24^2)$

$m = 105 kg$

now we have

$m = \rho (\pi R^2) t$

$105 = 8600(\pi \times 0.23^2) t$

$t = 0.0735 m$

4 0

2 years ago

Which of the following is an example of rotation

SOVA2 [1]

I believe it is D. Earth spinning on it's axis.

8 0

3 years ago

How are waves that are created by a musical instrument and waves that

Wittaler [7]

Answer:

both caused by physical vibrations

7 0

2 years ago

Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of

morpeh [17]

Answer:17.08 s

Explanation:

Given

distance between First and second Runner is 45.6 m

speed of first runner $(v_1)$ =3.1 m/s

speed of second runner $(v_2)$ =4.65 m/s

Distance between first runner and finish line is 250 m

Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner $t=\frac{295.6}{4.65}=63.56 s$

time required by first runner to reach finish line $=\frac{250}{3.1}=80.64 s$

Thus second runner reach the finish line 80.64-63.56=17.08 s earlier

3 0

3 years ago