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3 years ago

How do you determine the valence electrons? Ex. Li=?, Be=?, N=?, O=?, F=? (List the charges)

Chemistry

2 answers:

MatroZZZ [7]3 years ago

6 0

By finding what group each is in

JulsSmile [24]3 years ago

4 0

<span>Find a periodic table of elements. ... <span>Label each column on the periodic table of elements from 1 to 18. ... </span><span>Find your element on the table. ... </span>Use the group numbers to determine the number of valence electrons. </span><span>imgres</span>

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3 years ago

Explain intermolecular forces cause water molecules to stick to a material like a glass pitcher

natulia [17]

Answer:

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3 years ago

State the building blocks for all the macromolecules

murzikaleks [220]

Answer:

<h2>Carbohydrates, Lipids, Proteins, and Nucleic Acids</h2>

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3 years ago

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What are two things in nature that solar energy powers?

adell [148]

Answer: light and heat

Explanation:Our sun is the source of all life on Earth, and solar energy is useful to us in many different ways. The sun creates two main types of energy - light and heat - that we can harness for many activities ranging from photosynthesis in plants to creating electricity with photovoltaic (PV) cells to heating water and food.

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3 years ago

What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?

REY [17]

Answer:

$CaN_{2} O_{6}$

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

24.42/40.08 = 0.6092 mol

17.07/14.01 = 1.218 mol

58.85/15.99 = 3.680 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.

0.6092 mol/0.6092 mol = 1

1.218 mol/0.6092 mol = 2

3.680 mol/0.6092 mol = 6

So the empirical formula is $CaN_{2} O_{6}$

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3 years ago