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3 years ago

Calculate the momentum value of .... (Include appropriate units on your answers.)

Physics

1 answer:

vekshin13 years ago

5 0

Given :

Mass of brick, m = 2 kg.

Speed of block, v = 12 m/s .

To Find :

The momentum of the brick.

Solution :

We know, momentum of any object is given by :

Momentum = Mass × Speed

Momentum = m × v

Momentum = 2 kg × 12 m/s

Momentum = 24 kg m/s

Therefore, the momentum of the brick is 24 kg m/s .

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The rate of cooling determines ....... and ......

PilotLPTM [1.2K]

Answer:

freezing point and melting point

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2 years ago

Question 30

stellarik [79]

Answer: $0.69\°$

Explanation:

The angular diameter $\delta$ of a spherical object is given by the following formula:

$\delta=2 sin^{-1}(\frac{d}{2D})$

Where:

$d=16 m$ is the actual diameter

$D=1338 m$ is the distance to the spherical object

Hence:

$\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})$

$\delta=0.685\° \approx 0.69\°$ This is the angular diameter

3 0

3 years ago

Which of the following statements describes a compound machine?

ASHA 777 [7]

From the word compound, the compound machine is already a combination of two or more types of simple machine. Thus, the answer is letter C. Because of its complexity, it is able to perform several other functions than a simple one.

6 0

3 years ago

Read 2 more answers

What is a rubens tube

Free_Kalibri [48]

Answer:

its an antique physics apparatus for demonstrating acoustic standing waves in a tube.

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3 years ago

Calculate the radiative and collisional energy losses (in keV/micron) for a 1.9 MeV electron in lead and determine the rad./coll

Andrew [12]

Answer:

Explanation:

During an energy transfer, the collision loss for an electron can be determined by using the formula:

$Q = \dfrac{4mME }{(m+M)^2}$

However; from the total stopping power & power loss of the electron;

$\dfrac{radiational \ energy \ loss}{colisional \ energy \ loss } = \dfrac{ZE}{800}$

where;

Z = atomic no. for lead = 82

E = 1.9 MeV

∴

radiational energy loss = collisional energy loss $=\dfrac{82 \times 1.9}{800}$

= 0.19475

Normally, the traditional lead shielding in its pure shape contains high brittleness. However, the functionality of this carbon group chemical element is useful for protection because it has an excessive density.

Initially, the conventional lead protection however reduces the mild clarity at the same moment as plexiglass is useful for light transmittance and readability.

Moreover, the traditional lead with its high density and thickness reduces observation features, in the meantime, the plexiglass is a whole lot higher than the stated.

Finally, plexiglass contains a high dimensional balance with an excessive dielectric constant.

4 0

3 years ago