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3 years ago

Calculate the momentum value of .... (Include appropriate units on your answers.)

Physics

1 answer:

vekshin13 years ago

5 0

Given :

Mass of brick, m = 2 kg.

Speed of block, v = 12 m/s .

To Find :

The momentum of the brick.

Solution :

We know, momentum of any object is given by :

Momentum = Mass × Speed

Momentum = m × v

Momentum = 2 kg × 12 m/s

Momentum = 24 kg m/s

Therefore, the momentum of the brick is 24 kg m/s .

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A ball is dropped from a height h and falls the last half of its distance in 4 seconds. How long does the ball fall? From what h

dlinn [17]

Answer:

How long does the ball fall is t_2 = 13.66 (s).

From what height is the ball originally dropped is h= 913.90 (m).

Explanation:

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3 years ago

A rock is dropped from a vertical cliff. The rock takes 6.00 s to reach the ground below the cliff. What is the height of the cl

Lana71 [14]

Answer:

180 m

Explanation:

The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation

$h=\frac{1}{2}gt^2$

where

g = 10 m/s^2 is the acceleration due to gravity

t = 6.00 s is the time of the fall

Substituting these data, we find the height of the cliff:

$h=\frac{1}{2}(10 m/s^2)(6.00 s)^2=180 m$

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4 years ago

A fine-grained sedimentary rock is known as _____.

Yakvenalex [24]

The finer‐grained<span> s</span>edimentary rocks<span> are called shale, siltstone, and mudstone</span>

5 0

3 years ago

A particular type of automobile storage battery is characterized as "207 - Ampere - hour, 9.4 V."

zepelin [54]

Electric Energy = Current x Voltage x time = 207 x 9.4 = 1,945.8 J

6 0

3 years ago

A 70 kg base runner begins his slide into second base while moving at a speed of 4.35 m/s. He slides so that his speed is zero j

sladkih [1.3K]

Answer

given,

Mass of the runner, M = 70 Kg

speed of the runner on the second base = 4.35 m/s

speed at the base = 0 m/s

Acceleration due to gravity,g = 9.8 m/s²

a) magnitude of mechanical energy lost

Mechanical energy lost is equal top gain in kinetic energy

$ME_{Lost}=\dfrac{1}{2}mv^2$

$ME_{Lost}=\dfrac{1}{2}\times 70\times 4.35^2$

$ME_{Lost}=662.29\ J$

b) Work done = Force x displacement

W = F. x

F = μ mg

W = μ mg . x

Work done is equal to 662.29 J

$x=\dfrac{W}{\mu m g}$

using the coefficient of the friction,μ = 0.7

$x=\dfrac{662.29}{ 0.7\times 70\times 9.8}$

x = 1.38 m

Hence, the runner will slide to 1.38 m.

3 0

3 years ago