This is a linear relationship. The slope-intercept form of the linear equation is:

Where,
- m is the rate of change (positive if increasing rate and negative if decreasing rate)
- c is the y intercept, or the initial value
<u><em>Rate of change is 2.5 quarts per minute (it is decreasing so m is -2.5)</em></u>
<u><em>Initial value is 50 quarts, so c is 50.</em></u>
Plugging in the values we get
.
Changing variables to w instead of y and t instead of x, gives us,
. Where w is warts of water left in the tub and t is the time in minutes.
There is no viable solution when t=30 because at t=20, w=0 (
). It means after 20 minutes, there is no water left. So t=30 minutes doesn't make sense.
ANSWER:
Modelling equation: 
When
, there is no VIABLE solution
Answer:
4
Step-by-step explanation:
Answer:
The answer is 148.6666667
Step-by-step explanation:
1) Set a linear quation

2) Cross multiply

3) Multiple the right side

4) Divide both side by 15

5) Solve the linear equation

Well, it would become 5/7x=40.5. Divide both sides by 5/7, so it is 40.5 * by the reciprocal of 5/7 (7/5). The answer is 56.7 pounds.