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3 years ago

The magnet below is cut in half. what will be the result?

Physics

1 answer:

loris [4]3 years ago

3 0

Answer:

the correct would be c

Explanation:

a magnet will always have a north and a south so if you cut the magnet in half the north part would have a south on the opposite end and vice versa .

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Water has a specific heat of 4.186 J/g°C. How much heat is required to increase 10.0 g of water from 25.0°C to 30.0°C?

Makovka662 [10]

10 x 4.186 x (30-25)=209 j

7 0

3 years ago

Read 2 more answers

An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec

Tresset [83]

Answer : Total electrical energy is 36000 J.

Explanation :

It is given that,

Power of electric toaster, P = 1200 Watts

Voltage, V = 120 Volts

Time, t = 30 s

Electric energy is defined as the product of the power and the time taken.

$E=Pt$

$E=1200\ W\times 30\ s$

$E=36000\ J$

Total electrical energy used to operate the toaster for 30 seconds is 36000 J.

8 0

4 years ago

Read 2 more answers

A submarine heads toward a port, which broadcasts a signal at 175 MHz. If the submarine heads toward the port at 46 m/s, what ch

Usimov [2.4K]

Answer:

Δf = 0.00003 MHz = 30 Hz

Explanation:

The apparent frequency due to the motion of receiver towards the source is given by Doppler's effect, while the source is stationary. Therefore, the formula is given as follows:

$f = (\frac{c+v_{o} }{c})f_{0}$

where,

f = apparent frequency

c = speed of light = 3 x 10⁸ m/s

v₀ = velocity of observer = 46 m/s

f₀ = Original Frequency = 175 MHz = 175 x 10⁶ Hz

Therefore,

$f = (\frac{300000000 m/s + 46 m/s}{300000000 m/s})(175 MHz)\\$

f = 175.00003 MHz

Therefore, the change in frequency is:

Δf = f - f₀

Δf = 175.00003 MHz - 175 MHz

4 0

3 years ago

A sandbag motionless in outer space is hit by a three-times-as massive sandbag moving at 12 m/s. They stick together. This is an

vekshin1

Answer:

This is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

Explanation:

Let the mass of the motionless sandbag = m₁

Let the mass of the moving sandbag = m₂ = 3m₁

initial velocity of the motionless sandbag, u₁ = 0

initial velocity of the moving sandbag, u₂ = 12 m/s

Let their final velocity, = v

Collision between two particles can either be elastic or inelastic.

Since they stick together after the impact, then the collision is inelastic

Apply the principle of conservation of linear momentum;

Initial kinetic energy = final kinetic energy

¹/₂m₁u₁² + ¹/₂m₂u₂² = ¹/₂v²(m₁ + m₂)

¹/₂m₁(0)² + ¹/₂(3m₁)(12)² = ¹/₂v²(m₁+3m₁)

216m₁ = 2m₁ v²

v² = 108

v = √108

v = 10.392 m/s

Change in kinetic energy = Final kinetic energy - initial kinetic energy

Initial Kinetic energy, KE₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

KE₁ = ¹/₂m₁(0)² + ¹/₂(3m₁)(12)²

KE₁ = 216m₁ J

Final kinetic energy, KE₂ = ¹/₂v²(m₁ + m₂)

KE₂ = ¹/₂(108)(m₁ + 3m₁)

KE₂ = 216m₁ J

ΔKE = KE₂ - KE₁ = 216m₁ J - 216m₁ J = 0%

Therefore, this is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

4 0

3 years ago

A block of mass m is pushed up against a spring with spring constant k until the spring has been compressed a distance x from eq

Snowcat [4.5K]

Answer:d

Explanation:

Spring is compressed to a distance of x from its equilibrium position

Work done by block on the spring is equal to change in elastic potential energy

i.e. Work done by block $W=\frac{1}{2}kx^2$

therefore spring will also done an equal opposite amount of work on the block in the absence of external force

Thus work done by spring on the block $W=-\frac{1}{2}kx^2$

Thus option d is correct

6 0

3 years ago