Answer:
Airplanes' wings are curved on top and flatter on the bottom. That shape makes air flow over the top faster than under the bottom. As a result, less air pressure is on top of the wing. This lower pressure makes the wing, and the airplane it's attached to, move up.
Explanation:
Answer:
The total compressor work is 234.8 kJ/kg for a isentropic compression
Explanation:
Please look at the solution in the attached Word file
Answer:
Explanation:
The rate of heat transfer from the balls to the air is:
![\dot Q = \left[(800\,\frac{1}{min} )\cdot (\frac{1\,min}{60\,s} )\cdot(8085\,\frac{kg}{m^{3}})\cdot (\frac{4}{3}\pi )\cdot (6\times 10^{-3}\,m)^{3}\right]\cdot (0.480\,\frac{kJ}{kg\cdot ^{\textdegree}C} )\cdot (850\,^{\textdegree}C-900\,^{\textdegree}C)](https://tex.z-dn.net/?f=%5Cdot%20Q%20%3D%20%5Cleft%5B%28800%5C%2C%5Cfrac%7B1%7D%7Bmin%7D%20%29%5Ccdot%20%28%5Cfrac%7B1%5C%2Cmin%7D%7B60%5C%2Cs%7D%20%29%5Ccdot%288085%5C%2C%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%7D%29%5Ccdot%20%28%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%29%5Ccdot%20%286%5Ctimes%2010%5E%7B-3%7D%5C%2Cm%29%5E%7B3%7D%5Cright%5D%5Ccdot%20%280.480%5C%2C%5Cfrac%7BkJ%7D%7Bkg%5Ccdot%20%5E%7B%5Ctextdegree%7DC%7D%20%29%5Ccdot%20%28850%5C%2C%5E%7B%5Ctextdegree%7DC-900%5C%2C%5E%7B%5Ctextdegree%7DC%29)
For efficient treatment, the dissolved oxygen concentration in the aeration tank must be kept between 1-3 mg/L. The microbial biomass will die at low DO levels, and it will take time and money to rebuild it.
The depth, which normally ranges from 3 to 4.5 meters, determines how effectively air is aerated. The breadth, which is typically maintained between 5 and 10 meters, regulates the mixing. The ideal width-to-depth ratio is 1.2 to 2.2. The distance shouldn't be shorter than 30 meters or longer than 100 meters. Bacteria used in wastewater treatment and stabilization are given oxygen by aeration. The bacteria require oxygen for biodegradation to take place.
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Answer:
Mass of cement used is 62.5 lb
Mass of gravel used is 225 lb
Explanation:
The ratio given here is cement to sand to gravel = 1 : 2.4 : 3.6
So, for 150 lb of sand
C : S : G = 1 : 2.4 : 3.6
Mass of cement used is 62.5 lb
Mass of gravel used is 225 lb
