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3 years ago

How is air pressure affected by the shape of an aircraft wing

Engineering

1 answer:

oksano4ka [1.4K]3 years ago

3 0

Answer:

Airplanes' wings are curved on top and flatter on the bottom. That shape makes air flow over the top faster than under the bottom. As a result, less air pressure is on top of the wing. This lower pressure makes the wing, and the airplane it's attached to, move up.

Explanation:

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Alberta Einstein teaches a business class at Podunk University. To evaluate the students in this class, she has given three test

madreJ [45]

Answer:

See explaination

Explanation:

Please kindly check attachment for step by step solution of the given problem represented as a flow chart.

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4 years ago

: Câu nào dưới đây thể hiện sự thiếu tự chủ?

sukhopar [10]

Answer:

thành thật mà nói bởi vì cách những chiếc lá đang chuyển và cách mặt trời chiếu sáng.

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3 years ago

(2pts) In _______________, the pulse amplitude is made proportional to the amplitude of the modulating signal. pulse-amplitude m

Reptile [31]

Answer:

(a) pulse-amplitude modulation (PAM)

Explanation:

It should be no surprise that pulse amplitude is modulated in <em>pulse-amplitude modulation (PAM)</em>.

7 0

3 years ago

g A food department is kept at -12oC by a refrigerator in an environment at 30oC. The total heat gain to the food department is

boyakko [2]

Answer:

a) $\dot W = 0.417\,kW$ , b) $COP_{R} = 2.198$ , c) Irreversible.

Explanation:

a) The power input required by the refrigerator is:

$\dot W = \dot Q_{H} - \dot Q_{L}$

$\dot W = \left(4800\,\frac{kJ}{h} - 3300\,\frac{kJ}{h}\right)\cdot \left(\frac{1}{3600} \,\frac{h}{s} \right)$

$\dot W = 0.417\,kW$

b) The Coefficient of Performance of the refrigerator is:

$COP_{R} = \frac{\dot Q_{L}}{\dot W}$

$COP_{R} = \frac{3300\,\frac{kJ}{h} }{(0.417\,kW)\cdot \left(3600\,\frac{s}{h} \right)}$

$COP_{R} = 2.198$

c) The maximum ideal Coefficient of Performance of the refrigeration is given by the inverse Carnot's Cycle:

$COP_{R,ideal} = \frac{T_{L}}{T_{H}-T_{L}}$

$COP_{R,ideal} = \frac{261.15\,K}{303.15\,K - 261.15\,K}$

$COP_{R,ideal} = 6.218$

The refrigeration cycle is irreversible, as $COP_{R} < COP_{R,ideal}$ .

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3 years ago

What term specifically describes small chunks of rocks and debris in space that burn up in Earth’s atmosphere?

inessss [21]

Term specifically describes small chunks of rocks and debris in space that burn up in Earth’s atmosphere is :

Meteors

Explanation:

A meteor is a meteoroid or a particle broken off an asteroid or comet orbiting the Sun – that burns up as it enters the Earth's atmosphere, creating the effect of a "shooting star".
Meteoroids that reach the Earth's surface without disintegrating are called meteorites.
Due to Earth's escape velocity, the minimum impact velocity is 11 km/s with asteroid impacts averaging around 17 km/s on the Earth. The most probable impact angle is 45 degrees.
Meteoroids have a pretty big size range. They include any space debris bigger than a molecule and smaller than about 330 feet space debris bigger than this is considered an asteroid.
But most of the debris the Earth comes in contact with is "dust" shed by comets traveling through the solar system.
The surface of a meteorite is generally very smooth and featureless, but often has shallow depressions and deep cavities resembling clearly visible thumbprints
Most iron meteorites, like the example at right, have well-developed regmaglypts all over their surface.

6 0

4 years ago