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Genrish500 [490]
3 years ago
14

6. At a construction site, cement, sand, and gravel are used to make concrete. The ratio of cement to sand to gravel is 1 to 2.4

to 3.6. If a 150-lb bag of sand is used, how much cement and gravel must be used?
Engineering
1 answer:
S_A_V [24]3 years ago
7 0

Answer:

Mass of cement used is 62.5 lb

Mass of gravel used is 225 lb

Explanation:

The ratio given here is cement to sand to gravel = 1 : 2.4 : 3.6

So, for 150 lb of sand

C : S : G = 1 : 2.4 : 3.6

\frac{C}{S}=\frac{1}{2.4}\\\Rightarrow C=S\frac{1}{2.4}\\\Rightarrow C=150\frac{1}{2.4}\\\Rightarrow C=62.5\ lb

Mass of cement used is 62.5 lb

\frac{S}{G}=\frac{2.4}{3.6}\\\Rightarrow G=S\frac{3.6}{2.4}\\\Rightarrow C=150\frac{3.6}{2.4}\\\Rightarrow C=225\ lb

Mass of gravel used is 225 lb

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I = 12.706 Amps

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Given:

- The mass of saturated R-134a m = 12 kg

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- The final Conditions

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Determine the current supplied I.

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       P_2 = 240 KPa

       T_2 = 70° C        ----------> h_2 = 314.53 KJ/kg

- Using First Thermodynamic Law, set up an energy balance:

                           E_in - E_out = ΔE_system

                           Q_in + W_electric,in - W_out = Δ U

                           Q_in + V*I*Δt - W_out = Δ U

                           Q_in + V*I*Δt = Δ H

                           Q_in + V*I*Δt = m*( h_2 - h_1 )

- Make the current I the subject of the expression above:

                            V*I*Δt = m*( h_2 - h_1 ) - Q_in

                            I = [ m*( h_2 - h_1 ) - Q_in ] / V*Δt

- Plug in the values in the expression derived above and evaluate current of source I:

                            I = [ 12*( 314.53 - 247.32 ) - 300 ]*1000 / 110*6*60

                            I = 12.706 Amps                              

- The required source of current is I = 12.706 Amps.

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