Answer : The pH of the solution is, 1.31
Explanation : Given,
Mass of
= 248 mg = 0.248 g (1 mg = 0.001 g)
Volume of solution = 140 mL
Molar mass of
= 36.5 g/mole
First we have to calculate the concentration of hydrochloric acid.
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :

Now put all the given values in this formula, we get:

The concentration of HCl is, 0.0485 M
As we know that, HCl dissociates to give hydrogen ion and chloride ion.
The dissociation reaction is:

Concentration of HCl = Concentration of H⁺ = Concentration of Cl⁻ = 0.0485 M
Now we have to calculate the pH of the solution.
pH : It is defined as the negative logarithm of hydrogen ion concentration.
Mathematically,
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)


Therefore, the pH of the solution is, 1.31