Question

A possible means for making an airplane invisible to radar is to coat the plane with an antireflective polymer. If radar waves have a wavelength of 3.00 cm and the index of refraction of the polymer is n = 1.50, how thick would you make the coating?

Answer 1

Answer:

$t=0.50cm$

Explanation:

From the question we are told that:

Wavelength $\lamda=3c$m

Refraction Index $n=1.50$

Generally the equation for Destructive interference for Normal incidence is mathematically given by

$2nt=m(\frac{1}{2})\lambda$

Since  Minimum Thickness occurs at

At $m=0$

Therefore

$t=\frac{\lambda}{2}$

$t=\frac{3}{4(1.50)}$

$t=0.50cm$