A cannonball is launched diagonally with an initial horizontal speed of 51.0m/s

Physics

1 answer:

OLEGan [10]3 years ago

6 0

• initial horizontal speed: 51.0 m/s

• initial vertical speed: 24.0 m/s

• initial speed: √((51.0 m/s)² + (24.0 m/s)²) ≈ 56.4 m/s

• angle: tan(<em>θ</em>) = (24.0 m/s) / (51.0 m/s) → <em>θ</em> ≈ 25.2º

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