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2 years ago

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A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 = 18 V and V2 = 12 V. The po

sitive terminals are indicated with a + sign, The values for the resistors are: R1 = R5 = 70 Ω, R2 = R6 = 106 Ω R3 = 59 Ω, and R4 = 83 Ω. The positive directions for the currents I1, I2 and I3 are indicated by the directions of the arrows. What is I3?

1 answer:

kaheart [24]2 years ago

7 0

The I3 will be 158 A.

<h3>How to find the current through the circuit?</h3>

The foundation of circuit analysis is Kirchhoff's circuit laws.
We have the fundamental instrument to begin studying circuits with the use of these principles and the equation for each individual component (resistor, capacitor, and inductor).
These rules aid in calculating the current flow in various network streams as well as the electrical resistance of a complicated network, or impedance in the case of AC.

To calculate I3 firstly, V4 has to be calculated,

$V_{4} =I_{4} R_{4}$

$V_{4} = V_{2} / R_{4} + R_{5} * R_{4}$

$V_{4} = 12 * 135 / 135+61$

$V_{4} = 8.26V$

For I3,

$I_{3} = R_{1} /(R1+R3 + (R1+R3)(R2+R6) * (V2 - V1 (R1+R2+R6/R1)$

$I3=(61)/((61)(50)+(61+50)(141+141)) (12 -18 (1+(141+141)/61)) = -.158 A$

Hence, the current through I3 will be 158 A.

To learn more about Kirchoff's laws refer to:

brainly.com/question/86531

#SPJ 10

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Here we can find the net force on the bicyclist by using Newton's second law of motion, which states that the net force acting on a body is equal to the product between the mass of the body and its acceleration:

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