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FromTheMoon [43]
3 years ago
15

1. An object of mass 300 kg is observed to

Physics
1 answer:
vekshin13 years ago
4 0

Answer:

The force required will be "300 N".

Explanation:

The given values are:

Mass of object,

m = 300 kg

Acceleration,

a = 1 m/s

Now,

The force will be:

⇒  F=m\times a

On substituting the values, we get

⇒      = 300\times 1

⇒      =300 \ N

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When an object is moving with uniform circular motion, the centripetal acceleration of the object a. is circular. b. is perpendi
never [62]
Hi Pupil Here's Your answer :::


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When an object is moving with uniform circular motion, the centripetal acceleration of the object \textbf{is\:Zero}.


Because the body is moving with a uniform velocity and hence, there might not be any acceleration due to it.


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Hope this helps .......
5 0
3 years ago
What is the wavenumber of the stretching vibrational mode for the CO molecule, given that the force constant of the bond is 680
Gnesinka [82]

Answer:

1.10134 * 10⁻⁹m⁻¹

Explanation:

K = 680Nm⁻¹

μ = ?

μ = (m₁ + m₂) / m₁m₂

compound = CO

C = 12.0 g/mol = 0.012kg/mol

O = 16.0g/mol = 0.016kg/mol

μ = (m₁ + m₂) / m₁m₂

μ = (0.012 + 0.016) / (0.012*0.016) = 145.83

v = 1/2πc * √(k/μ)

ν = 1/ 2*3.142* 3.0*10⁸ * √(630/145.83)

v = 5.30*10⁻¹⁰ * 2.078

v = 1.10134*10⁻⁹m⁻¹

8 0
3 years ago
What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave
Firlakuza [10]

Answer:

thinnest soap film is  206.76 nm

Explanation:

Given data

wavelength = 550 nm

index of refraction n  = 1.33

to find out

What is the thinnest soap film

solution

we have wavelength  λ = 550 nm

that is  λ = 550 × 10^{-9} m

and n = 1.3

we will find the thickness of soap film as given by formula that is

thickness = λ/2n

thickness = 550 × 10^{-9}  / 2(1.33)

thickness = 206.76 × 10^{-9}  m

thinnest soap film is  206.76 nm

7 0
3 years ago
If pizza is round will it roll off a cliff?
Rina8888 [55]
If a pizza is round like a ball it will roll off a cliff.If it’s just flat and round it won’t.
6 0
3 years ago
When an object threw to the free space to make an angle of 25 degree at an initial speed of 15 m/sec, the ball takes time to rea
alekssr [168]

Answer:

The horizontal distance traveled by the projectile is 15.23 m.

Explanation:

Given;

angle of projection, θ = 25⁰

initial velocity of the projectile, u = 15 m/s

time of flight, t = 1.12 s

The the travelling path of the object is calculated as the range of the projectile

R = u_x t\\\\R = (15\ Cos \ 25^0) \times 1.12\\\\R = 13.595 \times 1.12\\\\R = 15.23 \ m

Therefore, the horizontal distance traveled by the projectile is 15.23 m.

8 0
3 years ago
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