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3 years ago

1. An object of mass 300 kg is observed to

Physics

1 answer:

vekshin13 years ago

4 0

Answer:

The force required will be "300 N".

Explanation:

The given values are:

Mass of object,

m = 300 kg

Acceleration,

a = 1 m/s

Now,

The force will be:

⇒ $F=m\times a$

On substituting the values, we get

⇒ $= 300\times 1$

⇒ $=300 \ N$

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A simple generator is used to generate a peak output voltage of 19.0 V . The square armature consists of windings that are 6.65

salantis [7]

One of the efficient concepts that can help us find the number of turns of the cable is through the concept of induced voltage or electromotive force given by Faraday's law. The electromotive force or emf can be described as,

$\epsilon = NBA\omega$

Where,

N = Number of loops

B = Magnetic Field

A = Cross-sectional Area

$\omega$ = Angular velocity

Re-arrange to find N,

$N = \frac{\epsilon}{BA\omega}$

Our values are given as,

$\epsilon = 19V$

$B = 0.434T$

$\omega = 49.8\frac{rev}{s} (\frac{2\pi rad}{1 rev}) = 99.6\pi rad/s$

$A = (6.65*10^{-2})^2 m^2$

Replacing at our equation we have:

$N = \frac{\epsilon}{( 0.434)A\omega}$

$N = \frac{19}{( 0.434)((6.65*10^{-2})^2)(99.6\pi)}$

$N = 31.63 \approx 32$

Therefore the number of loops of wire should be wound on the square armature is 32 loops

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3 years ago

Tightness of the sciatic nerve can result in lower back pain true or false

uysha [10]

The answer is false.

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3 years ago

What is the angle of deviation in a plane mirror at normal incidence?

Tems11 [23]

Answer:

The deviation of a mirror is equal to twice the angle of incidence.The total angle between the straight-line path and the reflected ray is twice the angle of incidence. This is called the deviation of the light and measures the angle at which the light has strayed from its initial straight-line path.

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3 years ago

X rays of wavelength 0.0169 nm are directed in the positive direction of an x axis onto a target containing loosely bound electr

mamaluj [8]

Answer:

a) 4.04*10^-12m

b) 0.0209nm

c) 0.253MeV

Explanation:

The formula for Compton's scattering is given by:

$\Delta \lambda=\lambda_f-\lambda_i=\frac{h}{m_oc}(1-cos\theta)$

where h is the Planck's constant, m is the mass of the electron and c is the speed of light.

a) by replacing in the formula you obtain the Compton shift:

$\Delta \lambda=\frac{6.62*10^{-34}Js}{(9.1*10^{-31}kg)(3*10^8m/s)}(1-cos132\°)=4.04*10^{-12}m$

b) The change in photon energy is given by:

$\Delta E=E_f-E_i=h\frac{c}{\lambda_f}-h\frac{c}{\lambda_i}=hc(\frac{1}{\lambda_f}-\frac{1}{\lambda_i})\\\\\lambda_f=4.04*10^{-12}m +\lambda_i=4.04*10^{-12}m+(0.0169*10^{-9}m)=2.09*10^{-11}m=0.0209nm$

c) The electron Compton wavelength is 2.43 × 10-12 m. Hence you can use the Broglie's relation to compute the momentum of the electron and then the kinetic energy.

$P=\frac{h}{\lambda_e}=\frac{6.62*10^{-34}Js}{2.43*10^{-12}m}=2.72*10^{-22}kgm\\$

$E_e=\frac{p^2}{2m_e}=\frac{(2.72*10^{-22}kgm)^2}{2(9.1*10^{-31}kg)}=4.06*10^{-14}J\\\\1J=6.242*10^{18}eV\\\\E_e=4.06*10^{-14}(6.242*10^{18}eV)=0.253MeV$

5 0

3 years ago

Your mass in kilograms if you weight 170 pounds

Aleonysh [2.5K]

1 pound ≈ 0.4536 kg

170 pounds ≈ 170 * 0.4536 kg

≈ 77.112 kg

5 0

3 years ago