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Furkat [3]
3 years ago
10

PLEASE HELP 15 POINTS If you hold a bar magnet in each hand and bring your hands together, will the force be attractive or repul

sive if the magnets are held: (ref: p.650-657)
a) with the two north poles together?
b) with a north pole and south pole together?
Physics
1 answer:
marusya05 [52]3 years ago
6 0

Answer:

with the 2 north poles it will repulse with the north and south it will retract

Explanation:

north and north wont come together. same for south and south. opposite sides always attract one another. hope it helped!!!

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a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm
enyata [817]

Answer: Escaped volume = 0.0612m^3

Explanation:

According to Boyle's law

P1V1 = P2V2

P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)

P2 = atmospheric pressure= 14.696psi

V1 = volume of tire =0.025m^3

V2 = escaped volume + V1 ( since air still remain in the tire)

V2 = P1V1/P2

V2 = 50.696×0.025/14.696

V2 = 0.0862m^3

Escaped volume = 0.0862 - 0.025 = 0.0612m^3

5 0
3 years ago
Help!! If an atom has 7 protons and 8 neutrons, and is not in an excited state, how many electrons would Bohr say the atom has?
quester [9]
The answer I believe is 6
8 0
3 years ago
Read 2 more answers
I would like help with this physics problem
Darina [25.2K]

(a) This is a freefall problem in disguise - when the ball returns to its original position, it will be going at the same speed but in the opposite direction. So the ball's final velocity is the negative of its initial velocity.

Recall that

v_f=v_i+at

We have v_f=-v_i, so that

-2v_i=at\implies-2\left(8\,\dfrac{\mathrm m}{\mathrm s}\right)=\left(-2\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\implies t=8\,\mathrm s

(b) The speed of the ball at the start and at the end of the roll are the same 8 m/s, so the average speed is also 8 m/s.

(c) The ball's average velocity is 0. Average velocity is given by \dfrac{v_i+v_f}2, and we know that v_f=-v_i.

(d) The position of the ball x_f at time t is given by

x_f=x_i+v_it+\dfrac12at^2

Take the starting position to be the origin, x_i=0. Then after 6 seconds,

x_f=\left(8\,\dfrac{\mathrm m}{\mathrm s}\right)(6\,\mathrm s)+\dfrac12\left(-2\,\dfrac{\mathrm m}{\mathrm s^2}\right)(6\,\mathrm s)^2=42\,\mathrm m

so the ball is 42 m away from where it started.

We're not asked to say in which direction it's moving at this point, but just out of curiosity we can determine that too:

x_f-x_i=\dfrac{v_i+v_f}2t\implies42\,\mathrm m=\dfrac{8\,\frac{\mathrm m}{\mathrm s}+v_f}2(6\,\mathrm s)\implies v_f=6\,\dfrac{\mathrm m}{\mathrm s}

Since the velocity is positive, the ball is still moving up the incline.

8 0
3 years ago
A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a un
kotegsom [21]

Answer:

t = 16.94 s

Explanation:

t is the time passes before police catch the speeder

speed of speeder Vo = V = 23.3 m/s

T = t

Police Info

Vo = 0 m/s

a = 2.75 m/s^2

t = t

Now,

displacement of the police car = displacement of the speeder.

x_{police} = Vo *t + 1/2 at^2

since Vo = 0

x police = 1/2 at^2

x police = 1/2 (2.75)(t)^2

Now the displacement of speeder is

x_{speeder} = Vt

x_{speeder} = 23.3 t

x_{speeder} = x_{police}

23.3 t = 1/2 * 2.75 t^2

23.3 t = 1.375 t^2

t = 23.3\1.375

t = 16.94

t = 16.94 s

4 0
3 years ago
What is the netforce?
Kipish [7]

Answer:

6 Newtons to the left.

Explanation:

We can convert  this into a generic algebra equation by giving directions positive and negative values.

The 6 will be positive, and the 10 and 2 will be negative.

Add 10 and 2 to have 12.

6-12 = -6.

Therefore you have 6 newtons to the left (negative).

3 0
3 years ago
Read 2 more answers
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