Answer:
T=5.98 kips
Explanation:
First, introduce forces, acting on both cars:
on car A there are 4 forces acting: gravity force mA*g, normal reaction force, friction force and force T- it represents the interaction between cars A and B. On car B, there are three forces acting: gravity force, normal reaction force and force T. Note, that force T is acting on both cars, but it has opposite direction. Force T, acting on car A has direction, opposite to the friction force, whether the T, acting on B, is directed backwards- in the same direction with the friction force. Note, that both cars have the same acceleration, which is directed backwards.
Once the forces were established, we can write components of the Second Newtons Law on vertical and horizontal axes, considering that horizontal axis is directed backwards- in the same direction with the acceleration:
For car A on the vertical axis the equation is: -mAg+NA=0
For car A on the horizontal axis, the equation is: Ffr-T=mAa
For car B, on the vertical axis the equation is: -mBg+NB=0
For car B, on the horizontal axis, the equation is: T=mBa
We need to solve these equations to find force T, knowing that Ffr=μmAg, where
After the transformations, the equations for acceleration and force in the coupling will be:
a=(μmAg)/(mA+mB)=6.43 ft/s2- note, that the given answer is not correct for the given numerical values;
and force T: T=μmAmBg/(mA+mB)=6.0 kips- note, that the force answer is in line with the given numerical value
