The 10-lb block is pressed against the spring so as to compress it 2 ft when it is at a point A. If the plane is smooth, determi
ne the distance d, measured from the wall, to where the block strikes the ground. Neglect the size of the block.
2 answers:
Answer:
Distance from the wall is 35.99ft
Explanation:
Distance can be defined a numerical measurement of how far apart objects or points are. In physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria.
In most cases, "distance from A to B" is interchangeable with "distance from B to A".
Please refer to attachment for the step by step solution
You might be interested in
Answer : The final velocity of the ball is, 12.03 m/s
Explanation :
By the 3rd equation of motion,
where,
s = distance covered by the object = 6.93 m
u = initial velocity = 2.99 m/s
v = final velocity = ?
a = acceleration =
Now put all the given values in the above equation, we get the final velocity of the ball.
Thus, the final velocity of the ball is, 12.03 m/s
Answer:
critical stress required for the propagation is 27.396615 × N/m²
Explanation:
given data
specific surface energy = 0.90 J/m²
modulus of elasticity E = 393 GPa = 393 × N/m²
internal crack length = 0.6 mm
to find out
critical stress required for the propagation
solution
we will apply here critical stress formula for propagation of internal crack
( σc ) = .....................1
here E is modulus of elasticity and γs is specific surface energy and a is half length of crack i.e 0.3 mm = 0.3 × m
so now put value in equation 1 we get
( σc ) =
( σc ) =
( σc ) = 27.396615 × N/m²
so critical stress required for the propagation is 27.396615 × N/m²