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arsen [322]
3 years ago
11

What shape is the sky?

Physics
2 answers:
Ad libitum [116K]3 years ago
4 0

Answer:

The sky would be in a sphere shape because of the shape of the atmosphere and the shape of the earth

n200080 [17]3 years ago
3 0

Answer:

The shape of sky is sphere shape.

Explanation:

<h3><em><u>HOPE</u></em><em><u> </u></em><em><u>IT HELP</u></em><em><u> </u></em><em><u>YOU</u></em><em><u> </u></em></h3>
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I’ll give points plz and brainliest I know the result I just need the process.
shusha [124]
Shiddd ion even know but can you like my comment?
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3 years ago
When a bicycle coasts uphill, it moves slower and slower as it climbs. Why?
astra-53 [7]

Letter B because it is gaining more potential energy as it SLOWLY climbs up the hill.

the less motion the more potential energy there is

6 0
3 years ago
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Which is the correct option?​
iris [78.8K]

Answer:

B

Explanation:

Bescouse a neutron is a robot and a fission is not

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4 years ago
The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th
Rom4ik [11]

Answer:

Approximate escape speed = 45.3 km/s

Explanation:

Escape speed

        v=\sqrt{\frac{2GM}{R}}

Here we have

   Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

   R = 1 AU = 1.496 × 10¹¹ m

   M = 2.3 × 10³⁰ kg

Substituting

    v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 2.3\times 10^{30}}{1.496\times 10^{11}}}=4.53\times 10^4m/s=45.3km/s

Approximate escape speed = 45.3 km/s

6 0
4 years ago
A block of mass 0.84 kg is suspended by a string which is wrapped so that it is at a radius of 0.061 m from the center of a pull
lora16 [44]

Answer:

E_l = 1.713 J

Explanation:

Given data:

mass of block is M_b = 0.84 kg

radius of block = 0.061 m

moment of inertia is 6.20 \times 10^{-3} kg m^2

D is distance covered by block = 0.65 m

speed of block is 1.705 m/s

From conservation of momentum  we have

M_b g D = \frac{1}{2} M_b v^2 + \frac{1}{2} I \omega^2 +  E_{loss}

0.84 \times 9.81 \times 0.65 = \frac{1}{2}\times  0.84 \times 1.705^2 +\frac{1}{2} \times 6.2 \times 10^{-3} [\frac{1.705}{0.061}]^2 + E_l

solving for energy loss

E_l = 1.713 J

3 0
3 years ago
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