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ElenaW [278]
3 years ago
13

Hi! Please help me!!!!! I don’t understand this question at all. If you could please explain that would be so helpful! Thanks!

Physics
2 answers:
inessss [21]3 years ago
7 0

Answer:

I would say the stone is being used as a fulcrum.

Explanation:

An example of a fulcrum is the triangle thing under a seesaw. I don't know for sure if that's the right answer, but I would strongly suggest it. Hope I helped,  have a nice day :)

Cerrena [4.2K]3 years ago
6 0

Answer:

to lift and balance an object, the effort force the user applies multiplied by its distance to the fulcrum must equal the load force multiplied by its distance to the fulcrum. Consequently, the greater the distance between the effort force and the fulcrum, the heavier a load can be lifted with the same effort force.

Explanation:

Have you ever wondered how ancient people could lift very heavy objects, such as large stones, to build pyramids? A lever is a simple machine that can help people do just this. It can also help make other kinds of physical work easier by giving the user a mechanical advantage.

Common examples of levers you might see around you are seesaws, scissors, wheelbarrows and even the your own jaw. Although all of these levers have the same functional parts, they vary in where the different components are located. How much effort does it take to lift a heavy load using a common type of lever.

Seesaws and scissors belong to a certain class of levers, called class 1. Class 1 levers usually have a beam that is rigid, long and thin, like a ruler. Between the two ends of the beam is the fulcrum, or pivot point, which is the point at which the beam can balance and move freely up and down around. On one end, the user places the load to be moved. On the other end, the user can apply effort, or a force, to try and move the load.

The way levers work is by multiplying the effort exerted by the user. Specifically, to lift and balance an object, the effort force the user applies multiplied by its distance to the fulcrum must equal the load force multiplied by its distance to the fulcrum. Consequently, the greater the distance between the effort force and the fulcrum, the heavier a load can be lifted with the same effort force.

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A series RLC circuit has a resistance of 57.61 W, a capacitance of 13.13 mF, and an inductance of 196.03 mH. The circuit is conn
Firdavs [7]

Answer:

voltage across = 1.6 V

Explanation:

given data

resistance R = 57.61 Ω

capacitance c = 13.13 mF = 13.13 ×10^{-3} F

inductance L = 196.03 mH = 0.19603 H

fixed rms output Vrms = 23.86 V

to find out

voltage across circuit

solution

we know resonant frequency that is

resonant frequency = 1 / ( 2π√(LC)

put the value

resonant frequency = 1 / ( 2π√(0.19603×13.13 ×10^{-3})

resonant frequency f = 3.1370 HZ

so current will be at this resonant is

current = Vrms / R

current =  23.86 / 57.61

current = 0.4141 A

and

so voltage across will be

voltage across = current / ( 2π f C )

voltage across = 0.4141 / ( 2π ( 3.1370) 13.13 ×10^{-3} )

voltage across = 1.6 V

4 0
2 years ago
In moving out of a dormitory at the end of the semester, a student does 1.20 x 104 J of work. In the process, his internal energ
Zielflug [23.3K]

Answer:

(a) W=1.20×10⁴J

(b) U= -5.46×10⁴J

(c) Q= -4.26×10⁴J

Explanation:

Given that student does 1.20×10⁴J work

(a) W=1.20×10⁴J

Work done by student,so positive sign

During the process, his internal energy decreases by 5.46×10⁴J.

(b) U= -5.46×10⁴J.

As the Energy decreases therefore negative sign

For (c) Q

We know the formula

Q=W+U\\Q=1.2*10^{4}+(-5.46*10^{4} )\\ Q=-4.26*10^{4}J

8 0
3 years ago
Mrs. Smith can walk 1.4 m/s. If it takes her 8.5 seconds to get to the teacher lounge, how far is the teacher lounge from her ro
AlexFokin [52]

Answer:

6 meters away

Explanation:

6*1.4= 8.4 which is pretty close

5 0
3 years ago
The magnification of a microscope is increased when_________.
azamat

Answer:

Option B

Explanation:

Magnification of Microscope is  

M = M_o \times M_e  

Mo= Magnification of objective lens and  

Me= magnification of the eyepiece.  

Both magnifications( of objective and eyepiece) are inversely proportional to the focal length.  

Magnification,  

M \propto \dfrac{1}{f}

when the focal length is less magnification will be high and when the magnification is the low focal length of the microscope will be more.

Thus. Magnification will increase by decreasing the focal length.

The correct answer is Option B

6 0
3 years ago
an ice skater applies a horizontal force to a 20.-kilogram block on frictionless, level ice, causing the block to accelerate uni
stiv31 [10]
The only vertical forces are weight and normal force, and they balance since the surface is horizontal. The horizontal forces are the applied force (uppercase F) in the direction the block slides and the frictional force (lowercase f) in the opposite direction.

Apply Newton's 2nd Law in the horizontal direction:
ΣF = ma
F - f = ma
where f = µmg

F - µmg = ma
F = m(a +µg)
F = (20 kg)(1.4 m/s² + 0.28(9.8 m/s²)

F = 83 N
3 0
3 years ago
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