Molar mass:
O2 = 31.99 g/mol
C8H18 = 144.22 g/mol
<span>2 C8H18(g) + 25 O2(g) = 16 CO2(g) + 18 H2O(g)
2 x 144.22 g --------------- 25 x 31.99 g
10.0 g ----------------------?? ( mass of O2)
10.0 x 25 x 31.99 / 2 x 144.22 =
7997.5 / 288.44 => 27.72 g of O2
hope this helps!
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Answer:
If a saturated hot solution is allowed to cool, the solute is no longer soluble in the solvent and forms crystals of pure compound. Impurities are excluded from the growing crystals and the pure solid crystals can be separated from the dissolved impurities by filtration.
Answer:
The new pressure exerted by the He, is 1266.6 Torr
Explanation:
A typical problem of gases where the volume is increased and the moles and T° keeps on constant. This is an indirect proportion because when the volume of the flask is increased, pressue decreases because molecules collide to a lesser extent with the walls of the vessel.
P₁ . V₁ = P₂ . V₂
760 Torr . 5L = P₂ . 3L
P₂ = (760 Torr . 5L) / 3L
P₂ = 1266.6 Torr
The answer is D. The rules states that every orbital on every sub level must be occupied before any can be double occupied.
I can help. First you want to write out each reactant and product with enough space to write in coefficients. Then box the reactants and products to emphazise how the elements shouldnt change. Afterwards, draw a line in front of the box for you to write in the coefficients.Now we srart balancing. To make things easier, you should always follow the method of : (Metals, Nonmetals,Oxygen,Hydrogen) in that order. By balancing each elememt/chemical this way it should make balancing them easier.
So to acryally perform it you're going to look at your first element (while still following the method) and then look over onto the other side to see what coefficient to place. Then after that element is balanced, you move onto the next element. Remember that everytime you balance an element, start over to make sure all of the other elements are still balanced before proceeding.