Answer:
656.09rad
Explanation:
We start from the equation of time based on the acceleration that says the following
We have this values practically,
Substituting,
Angular velocity is given by,
When the ball leaves your hand, it has kinetic energy.
Kinetic energy = (1/2) (mass) (speed)²
= (1/2) (20kg) (5 m/sec)²
= 50 joules .
If the ball is not carrying solar panels or a jet engine, then it can
never have any MORE energy than that. And if, as we always
assume, it doesn't suffer any air resistance, then it won't LOSE
any energy. It has 50 joules of energy, permanently or until it hits
something.
If you toss it straight up, then it keeps climbing until it runs out of
kinetic energy. That is, its kinetic energy gets converted to potential
energy as it goes higher and slower. At the top, where it stops
momentarily and has no kinetic energy at all, all the energy it has
is potential energy ... the entire 50 joules you gave it with your toss.
Answer:
-415 J
Explanation:
The amount of heat released when the ethylene glycol is cooled is given by:
where:
m = 3.65 kg = 3650 g is the mass of the ethylene glycol
Cs = 2.42 j/(g·°c) is the specific heat capacity of the substance
is the change in temperature of the coolant
By substituting the numbers into the equation, we find
And the sign is negative because the heat is released by the system.
Answer:
Explanation:
We will use the KE equation you wrote here and fill in what we are given:
and isolating the m:
which gives us
m = .50 kg
Answer:
intensity is 8.9 x W/m²
power is 11.3 x W
Explanation:
Given data
distance = 20 light year
power output = 4.00 x 10^28
to find out
intensity of the starlight and the power of the starlight
solution
we know the intensity formula that is
intensity = power / area
so here power is 4.00 x 10^28 and area = 4π(20ly)²
intensity = 4.00 x 10^28 / (4π (20×9.46×10^15)²
intensity = 8.9 x
so intensity is 8.9 x W/m²
and
power is Intensity × Area
so power = 8.9 x × (π (6.37 × 10^6)²
power = 11.3 x
so power is 11.3 x W