Hello!
Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.
Data:
Hooke represented mathematically his theory with the equation:
F = K * Δx
On what:
F (elastic force) = 2 N
K (elastic constant) = 4 N/cm
Δx (deformation or elongation of the elastic medium or distance from a spring) = ?
Solving:
simplify by 2
Answer:
B.) 1/2 cm
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Answer:
Explanation:
We know that
Acceleration due to gravity g is given by the formula
G= gravitational constant
M= mass of the Earth
r= radius of the earth
Let acc. due to gravity after radius is 20% greater be g_2
then
=> g1/g2 = (r_2/r_1)^2 => g2 = 9.81/1.2^2 = 6.8125
Explanation:
The simplest kinetic model is based on the assumptions that: (1) the gas is composed of a large number of identical molecules moving in random directions, separated by distances that are large compared with their size; (2) the molecules undergo perfectly elastic collisions (no energy loss) with each other and with the ...
The answer is There are no mammals present during this era. The studies revealed that animals on this era were mostly birds, reptiles, and amphibians. Birds were more dominantly known as the big predator animals in this period. It was only during the middle last part and late period of the Cenozoic period when the mammals came to populated and evolved. Also, it was the period when the man finally came.
Answer:
6.25m
Explanation:
Given parameters:
Masses of the car = 1000kg
Gravitational force = 1.067 x 10⁻⁵N
Unknown:
Distance between them = ?
Solution:
To solve this problem, we use the expression below from the universal gravitational law;
Fg = 
G = 6.67 x 10⁻¹¹
1.067 x 10⁻⁵ = 
d = 6.25m
