Answer:
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Fusion powers the Sun and stars as hydrogen atoms fuse together to form helium, and matter is converted into energy.
nuclear fission reactors include the possibility of radiation-releasing nuclear accidents, the problems of radioactive waste disposal, and the possibility of contributing to nuclear weapon proliferation
Complete Question
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headlights that are 0.681 m apart. At what distance, in kilometres, are you marginally able to discern that there are two headlights rather than a single light source?Take the wavelength of the light to be 549 nm and your pupil diameter as 4.63 mm.
Answer:
The distance is ![z = 4707.6 \ m](https://tex.z-dn.net/?f=z%20%20%3D%204707.6%20%5C%20m)
Explanation:
From the question we are told that
The is distance between the headlight is ![d = 0.681 \ m](https://tex.z-dn.net/?f=d%20%3D%200.681%20%5C%20m)
The wavelength is ![\lambda = 549 \ nm = 549 *10^{-9} \ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20549%20%5C%20nm%20%3D%20549%20%2A10%5E%7B-9%7D%20%5C%20m)
The pupil diameter is ![D = 4.63 \ mm = 0.00463 \ m](https://tex.z-dn.net/?f=D%20%20%3D%204.63%20%5C%20mm%20%3D%200.00463%20%5C%20m)
Generally, we can mathematically evaluate the resolution of the eye as
![\theta = \frac{1.22 * \lambda }{D}](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%5Cfrac%7B1.22%20%2A%20%20%5Clambda%20%7D%7BD%7D)
substituting values
![\theta = (1.45 *10^{-4} )^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20%281.45%20%2A10%5E%7B-4%7D%20%29%5Eo)
Now according to SOHCAHTOA rule
![sin \theta = \frac{ d}{z}](https://tex.z-dn.net/?f=sin%20%5Ctheta%20%20%3D%20%20%5Cfrac%7B%20d%7D%7Bz%7D)
Where z is the distance at which the eye can discern the two head light
given that the angle is very small ![sin \theta = \theta](https://tex.z-dn.net/?f=sin%20%5Ctheta%20%3D%20%20%5Ctheta)
=> ![\theta = \frac{ d}{z}](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20%5Cfrac%7B%20d%7D%7Bz%7D)
substituting values
![1.45*10^{-4} = \frac{ 0.681}{z}](https://tex.z-dn.net/?f=1.45%2A10%5E%7B-4%7D%20%20%3D%20%20%5Cfrac%7B%200.681%7D%7Bz%7D)
=> ![z = \frac{0.681}{1.45 *10^{-4}}](https://tex.z-dn.net/?f=z%20%20%3D%20%5Cfrac%7B0.681%7D%7B1.45%20%2A10%5E%7B-4%7D%7D)
=> ![z = 4707.6 \ m](https://tex.z-dn.net/?f=z%20%20%3D%204707.6%20%5C%20m)
Since the product of P·Vis constant along an isotherm, an expansion to twice the volume implies a pressure reduction to half the original pressure. I hope my answer has come to your help. God bless and have a nice day ahead!<span>
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An example would be 2 types of motion. It could be rectilinear or projectile motion. There are various equations for each type. Since you don't want me to tell you the answer, I could just express it in words. Then, it will be up to you to translate into mathematical equations.
For rectilinear motion, the distance traveled is equal to the initial velocity times the time, plus one-half of the acceleration times the square of the time. For projectile motion, the maximum distance is equal to the square of the initial velocity multiplied with the square of the sine of the launch angle, all over twice the gravity.