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mariarad [96]
3 years ago
12

An asteroid has a radius of 110,000 m

Physics
1 answer:
nydimaria [60]3 years ago
7 0

Answer: M = 6.13 × 10^18 kg

Explanation:

g = GM/r2,

Where

The mass M of the asteroid = ?

The radius r = 110000 m

g = 0.0338 m/s^2

G is the gravitational constant.

SI units its value is approximately 6.674×10^−11m3⋅kg−1⋅s−2

Using the formula

g = GM/r2

Cross multiply

GM = gr^2

6.674×10^-11M = 0.0338 × 110000^2

M = 408×10^6/6.674×10^-11

M = 6.13 × 10^18 kg

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Answer:

Putting your partner first means his or her needs, feelings, and wellbeing take priority over other people or things. A “sense of we” forms as you maintain this priority on purpose each day. You protect your relationship from being destroyed or damaged. You tend to your connection so it feels good to you b

5 0
2 years ago
Block A of mass M is on a horizontal surface of negligible friction. An identical block B is attached to block A by a light stri
miv72 [106K]

Answer:

T’= 4/3 T  

The new tension is 4/3 = 1.33 of the previous tension the answer e

Explanation:

For this problem let's use Newton's second law applied to each body

Body A

X axis

      T = m_A a

Axis y

     N- W_A = 0

Body B

Vertical axis

     W_B - T = m_B a

In the reference system we have selected the direction to the right as positive, therefore the downward movement is also positive. The acceleration of the two bodies must be the same so that the rope cannot tension

We write the equations

    T = m_A a

    W_B –T = M_B a

We solve this system of equations

     m_B g = (m_A + m_B) a

    a = m_B / (m_A + m_B) g

In this initial case

     m_A = M

     m_B = M

     a = M / (1 + 1) M g

     a = ½ g

Let's find the tension

    T = m_A a

    T = M ½ g

    T = ½ M g

Now we change the mass of the second block

    m_B = 2M

    a = 2M / (1 + 2) M g

    a = 2/3 g

We seek tension for this case

    T’= m_A a

    T’= M 2/3 g

   

Let's look for the relationship between the tensions of the two cases

   T’/ T = 2/3 M g / (½ M g)

   T’/ T = 4/3

   T’= 4/3 T

The new tension is 4/3 = 1.33 of the previous tension the answer  e

4 0
3 years ago
Given a force of 88n and an acceleration of 4m/s2 what is the mass?
Hitman42 [59]
F=ma
m=F/a = 88/4 = 22 kg

5 0
3 years ago
Read 2 more answers
The fire alarm goes off, and a 75 kg firefighter slides down a pole with a constant acceleration of a = 6 m/s square. What is th
Alex17521 [72]

Answer:

450N

Explanation:

Given data

Mass m= 75kg

Acceleration= 6m/s^2

From the Newtons first law, F=ma

substitute

F=75*6

F= 450N

Hence the force is 450N

3 0
3 years ago
The sound source of a ship’s sonar system operates at a frequency of 22.0 kHz . The speed of sound in water (assumed to be at a
Degger [83]

Answer:

147.456077993 Hz

Explanation:

f_0 = Frequency of the sonar = 22 kHz

v_w = Velocity of the whale = 4.95 m/s

v = Speed of sound in water = 1482 m/s

The difference in frequency is given by

\Delta f=f_0\times\dfrac{2v_{w}}{v-v_w}\\\Rightarrow \Delta f=22000\times\dfrac{2\times 4.95}{1482-4.95}\\\Rightarrow \Delta f=147.456077993\ Hz

The difference in frequency is 147.456077993 Hz

6 0
3 years ago
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