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marin [14]
3 years ago
10

A scoop of potassium oxide was placed in

Chemistry
1 answer:
kotykmax [81]3 years ago
8 0

Answer:

I just need points sorry

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Choose the correct statement regarding the relative size of atoms:
Sonbull [250]

Answer:

The atoms on left side are larger than the atoms on the right side of the periodic table because those on the right have more proton's.

Explanation:

As we travel along a period in a periodic table then the atomic radii decreases

This is because as we travel along a period we have that the atomic number of the atoms increases which means the the number of proton's increased

But the electron's add to the same outer shell throughout the period , which means the effective nuclear charge increases which pulls the outer electrons toward's the nucleus and the size decreases.

Therefore the atoms on left side are larger than the atoms on the right side of the periodic table because those on the right have more proton's.

6 0
3 years ago
1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change
Inga [223]

Answer:

1 ) Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

Δs = positive

there is transition from solid to liquid and the melting point of mercury ( the point at which reaction will take place ) = 500⁰C

hence ΔSdecomposition = S⁻ Hg  -  S⁻ HgO =

Δh of reaction = 181.6 KJ

Temp = 500 + 273 = 773 k

hence ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

8 0
3 years ago
Select the correct answer.
solong [7]
I think it’s A but I’m not sure, if it’s wrong I’m sorry
7 0
2 years ago
What is the balanced form of the following equation?. Br2 + S2O32– + H2O → Br1– + SO42– + H+.
zloy xaker [14]
For the equation to be balanced, the Atom's coefficient on the left side and the right side of the equation has to be equal

so, the answer would be : 

Br2 + S2032- + 5H20 -- >  BR2- + 2S02- + H+

Hope this helps
8 0
3 years ago
Please i need the answer im dying here ;-
ELEN [110]

Answer:

anawer is none of the above

8 0
3 years ago
Read 2 more answers
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