Answer:
0.082L or 82mL
Explanation:
Given parameters:
Pressure of gas = 780mmHg;
760mmHg = 1atm
780mmHg =
= 1.03atm
Volume of gas = 80ml = 0.08L
Standard pressure = 1atm
Unknown:
Volume of gas = ?
Solution:
To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of gas is inversely proportional to the pressure if the temperature is constant".
Mathematically;
P₁ V₁ = P₂ V₂
P and V are temperature values
1 and 2 are initial and final states;
Insert the parameters and solve;
1.03 x 0.08 = 1 x V₂
V₂ = 0.082L or 82mL
Answer:
21.2 g
Explanation:
Step 1: Given data
- Molar concentration of the solution (C): 0.400 mol/L
- Volume of solution (V): 500 mL (0.500 L)
Step 2: Calculate the moles of Na₂CO₃ (solute) in the solution
We will use the definition of molarity.
C = moles of solute / liters of solution
moles of solute = C × liters of solution
moles of solute = 0.400 mol/L × 0.500 L = 0.200 mol
Step 3: Calculate the mass corresponding to 0.200 moles of Na₂CO₃
The molar mass of Na₂CO₃ is 105.99 g/mol.
0.200 mol × 105.99 g/mol = 21.2 g
Answer:
Actual yield = 20.52 g
Explanation:
Given data:
Theoretical yield = 25.3 g
Percentage yield = 81.1 %
Actual yield = ?
Solution:
Formula:
Percentage yield = Actual yield /theoretical yield × 100
81.1 % /100 = Actual yield / 25.3 g
0.811 = Actual yield / 25.3 g
Actual yield = 0.811 × 25.3 g
Actual yield = 20.52 g