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vekshin1
3 years ago
5

How can the enthalpy change be determined for a reaction in an aqueous solution? By mixing the reactants in a calorimeter and me

asuring the temperature change By knowing the specific heat of the reactants By knowing the mass of the reactants The enthalpy change for this type of reaction cannot be determined.
Chemistry
2 answers:
Step2247 [10]3 years ago
6 0

Answer:

The enthalpy change of a reaction can be determined by mixing the reactants in a calorimeter and measuring the temperature change.

Explanation:

When mixing two solutions with a certain amount of solutes that can react, a change in the enthalpy of the system occurs. <em>This energy change at constant pressure can be determined using a calorimeter</em>. This device contains the solutions and practically does not absorb any heat from it. However, the heat absorbed by the calorimeter should be determined to consider it when measuring precise enthalpy parameters.

Once the reaction takes place inside the calorimeter, <em>a change in temperature is evident because the reaction can gain or release energy that is absorbed or gained by the aqueous solution</em>. By Measuring the initial and final temperature of the solution and using as an approach the specific heat similar to water (valid for diluted solutions) we can find the enthalpy of reaction as follows:

\Delta H_{rxn} = - (q_{calorimeter} +q_{solution})

q_{solution} = m_{solution} * S_{H-water}* \Delta T  

ivann1987 [24]3 years ago
4 0
I think the correct answer would be the second option. Enthalpy change can be determine for a reaction in an aqueous solution by knowing the specific heat of the reactants. You can use the equation H = mC(deltaT) where m is the mass, C is the specific heat and (deltaT) is the change in temperature.
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5. If 1 g of a gas occupies a volume of 300 mL at STP, what is the molecular weight of the gas?
ikadub [295]

Answer:

74,67 gr/mol

Explanation:

At STP 1 mole of an ideal gas has volume of 22,4 L. Since we know the volume of the gas we can find the number of moles of the gas. (300 mL=0,3 L)

n=0,3L/22,4 L=0,01339 mol

Since we know weight of the gas as 1 g, we can find the molecular weight as;

MW=1 g/0,01339 mol =74,67 gr/mol

3 0
3 years ago
If 4.50 l of water vapor at 50.2 °c and 0.121 atm reacts with excess iron, how many grams of iron(iii) oxide will be produced?
Flura [38]
When the balanced equation for this reaction is:
2Fe + 3H2O → Fe2O3  +  3H2

and according to the vapour pressure formula:
PV= nRT
when we have P is the vapor pressure of H2O= 0.121 atm
and V is the volume of H2O = 4.5 L
and T in Kelvin = 52.5 +273 = 325.5 K
R= 0.08205 atm-L/g mol-K
So we can get n H2O
So, by substitution:
n H2O = PV/RT
            = (0.121*4.5)/(0.08205 * 325.5) = 0.02038 gmol
n Fe2O3 = 0.02038 * (1Fe2O3/ 3H2O) = 0.00679 gmol
Note: we get (1FeO3/3H2O) ratio from the balanced equation.
we can get the Mass of Fe2O3 from this formula:
Mass = number of moles * molecular weight       
  when we have a molecular weight of Fe2O3 = 159.7
          =  0.00679 * 159.7 = 1.084 g
∴ 1.084 gm of Fe2O3 will produced
6 0
4 years ago
Read 2 more answers
Which substance has a definite shape and definite volume?
tino4ka555 [31]

Answer:

D iced tea

Explanation:

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3 0
2 years ago
What is the energy conversion that occurs in cellular respiration?
fomenos
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3 0
3 years ago
Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda re
Setler [38]

Answer:

0.5 mole of CO₂.

Explanation:

We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:

Mass of NaHCO₃ = 42 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 42/84

Mole of NaHCO₃ = 0.5 mole

Next, balanced equation for the reaction. This is given below:

NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

7 0
3 years ago
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