Answer:

Explanation:
From the information given:
Life requirement = 40 kh = 40 
Speed (N) = 520 rev/min
Reliability goal
= 0.9
Radial load
= 2600 lbf
To find C10 value by using the formula:

where;


The Weibull parameters include:



∴
Using the above formula:


![C_{10} = 3640 \times \bigg[\dfrac{1248}{0.9933481582}\bigg]^{\dfrac{3}{10}}](https://tex.z-dn.net/?f=C_%7B10%7D%20%3D%203640%20%5Ctimes%20%5Cbigg%5B%5Cdfrac%7B1248%7D%7B0.9933481582%7D%5Cbigg%5D%5E%7B%5Cdfrac%7B3%7D%7B10%7D%7D)

Recall that:
1 kN = 225 lbf
∴


Friction losses in pipes can be reduced by decreasing the length of the pipes, reducing the surface roughness of the pipes, and increasing the pipe diameter. Thus, options (c),(e), and (f) hold correct answers.
Friction loss is a measure of the amount of energy a piping system loses because flowing fluids meet resistance. As fluids flow through the pipes, they carry energy with them. Unfortunately, whenever there is resistance to the flow rate, it diverts fluids, and energy escapes. These opposing forces result in friction loss in pipes.
Friction loss in pipes can decrease the efficiency of the functions of pipes. These are a few ways by which friction loss in pipes can be reduced and the efficiency of the piping system can be boosted:
- <u><em>Decrease the length of the pipes</em></u>: By decreasing pipe lengths and avoiding the use of sharp turns, fittings, and tees, whenever possible result in a more natural path for fluids to flow.
- <u><em>Reduce the surface roughness of the pipes</em></u>: By reducing the interior surface roughness of pipes, a smooth and clearer path is provided for liquids to flow.
- <u><em>Increase the pipe diameter: </em></u>By widening the diameters of pipes, it is ensured that fluids squeeze through pipes easily.
You can learn more about friction losses at
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The C++ code that would draw all the iterations in the selection sort process on the array is given below:
<h3>C++ Code</h3>
#include <stdio.h>
#include <stdlib.h>
int main() {
int i, temp1, temp2;
int string2[16] = { 0, 4, 2, 5, 1, 5, 6, 2, 6, 89, 21, 32, 31, 5, 32, 12 };
_Bool check = 1;
while (check) {
temp1 = string2[i];
temp2 = string2[i + 1];
if (temp1 < temp2) {
string2[i + 1] = temp1;
string2[i] = temp2;
i = 0;
} else {
i++;
if (i = 15) {
check = !check;
}
}
}
return 0;
}
Read more about C++ programming here:
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Answer:
Marco is an Italian architect. He has received a contract to design a spacious building.
Explanation:
ect.
Answer:

Explanation:
The model for the turbine can be derived by means of the First Law of Thermodynamics:
![-\dot Q_{out}-\dot W_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right] =0](https://tex.z-dn.net/?f=-%5Cdot%20Q_%7Bout%7D-%5Cdot%20W_%7Bout%7D%20%2B%5Cdot%20m%20%5Ccdot%20%5Cleft%5B%28h_%7Bin%7D-h_%7Bout%7D%29%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%28v_%7Bin%7D%5E%7B2%7D-v_%7Bout%7D%5E%7B2%7D%29%20%2B%20g%5Ccdot%20%28z_%7Bin%7D-z_%7Bout%7D%29%5Cright%5D%20%3D0)
The work produced by the turbine is:
![\dot W_{out}=-\dot Q_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right]](https://tex.z-dn.net/?f=%5Cdot%20W_%7Bout%7D%3D-%5Cdot%20Q_%7Bout%7D%20%2B%5Cdot%20m%20%5Ccdot%20%5Cleft%5B%28h_%7Bin%7D-h_%7Bout%7D%29%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%28v_%7Bin%7D%5E%7B2%7D-v_%7Bout%7D%5E%7B2%7D%29%20%2B%20g%5Ccdot%20%28z_%7Bin%7D-z_%7Bout%7D%29%5Cright%5D)
The mass flow and heat transfer rates are, respectively:




Finally:

