Answer:
The power is 
Explanation:
In order to obtain the power it consumes we need to first obtain the resistance of the hair dryer at 120 V
Now the power supplied in Europe at their voltage of 230V would be
Looking the power obtain we see that it is higher than 1530 W so this would cause the dryer to smoke.
Answer:
23 W/K
Explanation:
Entropy of water at 15°C is 224.5 J/kg/K.
Entropy of water at 15.2°C is approximately 227.4 J/kg/K (interpolated).
The increase in entropy is therefore:
227.4 J/kg/K − 224.5 J/kg/K = 2.9 J/kg/K.
So the rate of entropy generation is:
2.9 J/kg/K × 8 kg/s = 23.2 W/K
Rounded to two significant figures, the rate is 23 W/K.
Answer:
Kitchen sinks can be clogged for a few reasons, food hair, and other things. Overtime, buildup of these things lead to clogging.
A few methods to fix clogging are, baking soda mixture, plunging, and boiling water.
The first method, baking soda mixture, what you do is you pour a cup of baking soda and vinegar down the drain, and place a rubber stopper to cover the drain opening. Wait 10 or more minutes, and take out the stopper, and run hot tap water until it's unclogged.
The second method is plunging. Make sure the sink has enough water to submerge the plunger, and start plunging. While you are plunging, maintain a good seal to get the best results. This usually works, but sometimes it doesn't.
The last method is boiling water. Pour boiling water into the drain, then after a while, the clogged drain should unclog, if it doesn't repeat the process until necessary.
Explanation:
Answer:
6.4 m/s
Explanation:
From the equation of continuity
A1V1=A2V2 where A1 and V1 are area and velocity of inlet respectively while A2 and V2 are the area and velocity of outlet respectively
where r1 and r2 are radius of inlet and outlet respectively
v1 is given as 1.6 m/s
Therefore
Answer:
2.9*10^14 electrons
Explanation:
An Ampere is the flow of one Coulomb per second, so 35 μA = is 35*10^-6 C per second.
An electron has a charge of 1.6*10^-19 C.
35*10^-6 / 1.6*10^-19 = 2.9*10^14 electrons
So, with a current o 35 μA you have an aevrage of 2.9*10^14 electrons flowing past a fixed reference cross section perpendicular to the direction of flow.
