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Jet001 [13]
3 years ago
9

What are transferred in an oxidation-reduction reaction (1 point)?

Chemistry
1 answer:
madreJ [45]3 years ago
7 0
electrons are transferred    in a oxidation-reduction  reaction

oxidation reduction  chemical equation involve  electrons  transfer   between  two species. In this reduction-oxidation type of chemical equation    oxidation  number of   molecule, atoms or ion  changes  by  gaining or losing  electrons,that is there  an oxidizing  agent and a  reducing agent  in the reaction.
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What is the answer to this ?
Alexxandr [17]

Answer:

12.78 or 12.80 mostly like 12.78

Explanation:

7 0
3 years ago
An unlit match contains approximately 1,000 J of chemical energy. When it burns, the match releases thermal energy and light ene
expeople1 [14]

Answer:

350J

Explanation:

Based on the first law of thermodynamics, which is the law of conservation of energy, energy can neither be created nor lost but can only be transformed. This implies that energy input of a system must equate the energy output as no energy can be lost.

In this case regarding an unlit match that contains 1000J of chemical energy. It burns to emit light energy and heat/thermal energy. If the amount of emitted thermal energy measured is 400J and the remaining/left over amount of chemical energy is 250J, this means that the missing amount of energy has been emitted as light energy.

To find the amount of light energy emitted, we say;

Amount of chemical energy - (thermal energy emitted + remaining chemical energy)

= 1000 - (400 + 250)

= 1000 - 650

= 350J

Hence, the amount of light energy emitted is 350J. This satisfies the law of conservation of energy because the output energy is equal to the total energy in the system.

4 0
3 years ago
Based on the law of conservation of matter, describe the relationship between the mass of the recants, and the mass of the produ
BaLLatris [955]

Answer:

Mass of reactant and mass of product must be equal.

Explanation:

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

For example:

In given photosynthesis reaction:

6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂

there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

5 0
3 years ago
Rare earth elements plz
Slav-nsk [51]
Rare earth metals are a group of 17 elements - lanthanum, cerium, praseodymium, neodymium, promethium, samarium, europium, gadolinium, terbium, dysprosium, holmium, erbium, thulium, ytterbium, lutetium, scandium, yttrium - that appear in low concentrations in the ground
3 0
3 years ago
Read 2 more answers
The halogens, the elements of Family 17 on the periodic table, combine easily with elements from Family 1. When a halogen reacts
timofeeve [1]

Answer:

When halogen elements react with group one metals they form halide salts.

Explanation:

The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements can not be found free in nature. Their chemical properties are resemble greatly with each other. As we move down the group in periodic table size of halogens increases that's way fluorine is smaller in size as compared to other halogens elements. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.

When halogen elements react with group one metals they form halide salts.

Alkali metals have one valance electron and halogens needed one electron to complete the octet thus alkali metals loses one electron which is accepted by halogens atom and form ionic compound called halide salts.

For example:

2Na + Cl₂ → 2NaCl

2K + Cl₂  → 2KCl

2Rb + Cl₂ → 2RbCl

2Li + Cl₂ → 2LiCl

With bromine:

2Na + Br₂ → 2NaBr

2K + Br₂  → 2KBr

2Rb + Br₂ → 2RbBr

2Li + Br₂ → 2LiBr

With iodine:

2Na + I₂ → 2NaI

2K +  I₂ → 2KBI

2Rb + I₂ → 2RbI

2Li + I₂ → 2LiI

4 0
3 years ago
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